Question

是否可以通过查询提供两个日期之间的天数进行计数具有今天的日期和输出的出色天数：年，月，日和提供30天，60天，90天的出色日子？

如果我从“ Check_Date”和“ Created_Date”声明“年，月，日”。 SQL提供了一个单独的窗口，并且，我只看到声明的“ FromDate”时间使用“ ToDate”显示总计的年，月，日。我在寻找一种方法要获得结果，请按“ Created_Date”记录进行滚动，并包括：年，月，日和出色的日子提供30天，60天，90天天？

抄写代码：

DECLARE @FromDate DATETIME = '2015-01-01 00:00:00', 
        @ToDate   DATETIME = '2019-09-18 00:00:00',
        @Years INT, @Months INT, @Days INT, @tmpFromDate DATETIME
SET @Years = DATEDIFF(YEAR, @FromDate, @ToDate)
 - (CASE WHEN DATEADD(YEAR, DATEDIFF(YEAR, @FromDate, @ToDate),
          @FromDate) > @ToDate THEN 1 ELSE 0 END) 


SET @tmpFromDate = DATEADD(YEAR, @Years , @FromDate)
SET @Months =  DATEDIFF(MONTH, @tmpFromDate, @ToDate)
 - (CASE WHEN DATEADD(MONTH,DATEDIFF(MONTH, @tmpFromDate, @ToDate),
          @tmpFromDate) > @ToDate THEN 1 ELSE 0 END) 

SET @tmpFromDate = DATEADD(MONTH, @Months , @tmpFromDate)
SET @Days =  DATEDIFF(DAY, @tmpFromDate, @ToDate)
 - (CASE WHEN DATEADD(DAY, DATEDIFF(DAY, @tmpFromDate, @ToDate),
          @tmpFromDate) > @ToDate THEN 1 ELSE 0 END) 

SELECT @FromDate FromDate, @ToDate ToDate, 
       @Years Years,  @Months Months, @Days Days



SELECT DISTINCT  
ge.Name, --table columns
ge.Entity_Type, 
ge.Entity_Number, 
bc.Super_Entity_ID, 
ch.Check_Date, --check created
ch.Created_Date, --if payment was received
ch.Check_Number, 
ch.Amount,
vn.Vendor_Name



Check_Date,Created_Date,DATEDIFF("DAY",Check_Date,Created_Date) AS DAY


FROM dbo.gl_entities AS ge
INNER JOIN
dbo.super_entity AS se
ON ge.Super_Entity_ID = se.Super_Entity_ID 
INNER JOIN
dbo.bank_codes AS bc
ON se.Super_Entity_ID = bc.Super_Entity_ID 
INNER JOIN
dbo.checks AS ch
ON bc.Bank_Code_ID = ch.Bank_Code_ID 
INNER JOIN
dbo.vendors AS vn
ON ch.Vendor_ID = vn.Vendor_ID


WHERE 
ge.Active = 1 and vn.active = 1 and (ge.IS_Shadow = 1 OR se.IS_Tiered = 0)

AND CHECK_DATE > '20150101 00:00:00'
AND CHECK_DATE< '20190918 00:00:00'

ORDER BY ch.Check_Date, ch.Created_Date

Answer 1

仅在查询中自己的列中重复它们：

Execution time (hr): 54s 105.970357ms

如果DISTINCT子句遇到问题，则始终可以使用子查询。如果您希望年，月，日基于各列之一而不同，则必须进行详细说明，然后我们才能将在SET语句中所做的所有操作移至SELECT语句中。

没有表和数据，我无法很好地进行测试。

Answer 2

伪代码尝试演示移动集语句以选择语句

declare @begin date = '2018-01-01'
declare @end date = '2019-01-01'

declare @middletest int = datediff("dd", @begin, @end)/2
declare @middledate date = dateadd("dd", @middletest, @begin)
declare @middlemonth int = month(@middledate)

select @middlemonth half_month, @middledate middle_date
   -- ,other_columns here
from table
where something

开始更换。 @middlemonth在select语句中，因此将其替换为month（@middledate）。

declare @begin date = '2018-01-01'
declare @end date = '2019-01-01'

declare @middletest int = datediff("dd", @begin, @end)/2
declare @middledate date = dateadd("dd", @middletest, @begin)

select month(@middledate) half_month, @middledate middle_date
   -- ,other_columns here
from table
where something

@middledate现在在select语句的2个位置中，因此每次将其替换为dateadd（“ dd”，@middletest，@begin）。

declare @begin date = '2018-01-01'
declare @end date = '2019-01-01'

declare @middletest int = datediff("dd", @begin, @end)/2

select month(dateadd("dd", @middletest, @begin)) half_month,
    dateadd("dd", @middletest, @begin) middle_date
    -- ,other_columns here
from table
where something

继续。

declare @begin date = '2018-01-01'
declare @end date = '2019-01-01'

select month(dateadd("dd", datediff("dd", @begin, @end)/2, @begin)) half_month,
    dateadd("dd", datediff("dd", @begin, @end)/2, @begin) middle_date
    -- ,other_columns here
from table
where something

您可以根据需要用表中的值替换内容。如果表中有一列start_date，并且您希望将其作为开始，然后使用当前日期作为结束：

select month(dateadd("dd", datediff("dd", start_date, getdate())/2, start_date)) half_month,
    dateadd("dd", datediff("dd", start_date, getdate())/2, start_date) middle_date
    -- ,other_columns here
from table
where something

两个日期之间的天数与年，月，日

2 个答案: