Question

我已编写查询以获取特定日期的数据，但需要查询以每小时和每天的方式获取数据

我的查询

SELECT 
TRAN_USERTRANSACTIONS.APPLICATIONNUMBER 
FROM 
TRAN_USERTRANSACTION 
WHERE TRAN_USERTRANSACTIONS.CREATEDAT 
LIKE '%19-09-19%' 
GROUP BY 
TRAN_USERGTRANSACTION.APPLICATIONNUMBER;

CREATEDAT是Timestampin，其格式如下：DD-MM-YY hh.mm.ss.ssss AM / PM

Answer 1

按小时（希望有帮助）：

Select TRAN_USERTRANSACTIONS.APPLICATIONNUMBER
       , TO_CHAR(TRAN_USERTRANSACTIONS.CREATEDAT ,'HH AM')
from TRAN_USERTRANSACTION
WHERE TRAN_USERTRANSACTIONS.CREATEDAT LIKE '%19-09-19%' 
group by TRAN_USERTRANSACTIONS.APPLICATIONNUMBER 
         , TO_CHAR(TRAN_USERTRANSACTIONS.CREATEDAT ,'HH AM')
order by TO_CHAR(dat_azu,'HH AM') asc;

Answer 2

我假设您想要按小时而不是按应用程序进行汇总。如果是这样，则小时应在GROUP BY中：

SELECT TO_CHAR(t.CREATEDAT, 'YYYY-MM-DD HH24') as dh,
       COUNT(*) 
FROM TRAN_USERTRANSACTION t
WHERE t.CREATEDAT >= DATE '2019-09-19' AND
      t.CREATEDAT < DATE '2019-09-20'
GROUP BY TO_CHAR(t.CREATEDAT, 'YYYY-MM-DD HH24')
ORDER BY dh;

使用时间戳和当前日期每小时和每天从Oracle数据库中获取数据

2 个答案: