Question

        for x in range (1, 10)
           for y in range (1,10)
             for z in range (1,10)
             #In this loop, I perform some operations to generate an
             #output that has a shape (500,4). By using this output, I perform 
             #another set of operations as shown below)
              for i in range(1,500)
                 if i == 20
                    p = somevalue_1 #(which is derived by using columns in outpout(500,4)
                 if i == 40
                    q = somevalue_2 #(which is derived by using columns in outpout(500,4)
                 if i == 60
                    r = somevalue_3 #(which is derived by using columns in outpout(500,4)
                 if i == 80
                    s = somevalue_4 #(which is derived by using columns in outpout(500,4)

因此，对于1000次迭代（10x10x10），我想收集值p，q，r，s（shape（1000,4））。

Answer 1

您可以使用列表和范围（1，11）的列表来获取10个值：

allData = []
for x in range (1, 11):

    for y in range (1,11):

        for z in range (1,11):
            p=q=r=s = ''
            for i in range(1,500):

                if i == 20:
                    p = somevalue_1 #(which is derived by using columns in outpout(500,4)
                if i == 40:
                    q = somevalue_2 #(which is derived by using columns in outpout(500,4)
                if i == 60:
                    r = somevalue_3 #(which is derived by using columns in outpout(500,4)
                if i == 80:
                    s = somevalue_4 #(which is derived by using columns in outpout(500,4)
            temp =[p,q,r,s]
            allData.append(temp)

这里的allData列表包含形状为1000,4的完整数据

将嵌套的for循环的输出存储在数组中

1 个答案: