我正在玩Rails 6,我的强参数有问题。我用rails g scaffold ClockEntry user:references purpose:string time_in:datetime time_out:datetime
架起了名为ClockEntry的Rails CRUD,当我点击“创建按钮”时,我得到了
NameError: undefined local variable or method `clock_entry_params’ for #<ClockEntriesController:0x00007f9e4347c208>
这是下面生成的迁移:
class CreateClockEntries < ActiveRecord::Migration[6.0]
def change
create_table :clock_entries do |t|
t.references :user, null: false, foreign_key: true
t.string :purpose
t.datetime :time_in
t.datetime :time_out
t.timestamps
end
# add_index :clock_entries, %i[purpose time_in time_out]
add_index :clock_entries, :purpose
add_index :clock_entries, :time_in
add_index :clock_entries, :time_out
end
end
在运行迁移后,以下是生成的架构:
create_table "clock_entries", force: :cascade do |t|
t.bigint "user_id", null: false
t.string "purpose"
t.datetime "time_in"
t.datetime "time_out"
t.datetime "created_at", precision: 6, null: false
t.datetime "updated_at", precision: 6, null: false
t.index ["purpose"], name: "index_clock_entries_on_purpose"
t.index ["time_in"], name: "index_clock_entries_on_time_in"
t.index ["time_out"], name: "index_clock_entries_on_time_out"
t.index ["user_id"], name: "index_clock_entries_on_user_id"
end
创建表单:
注意,我写了其他设置time_in
和time_out
的函数。它们在控制器内部的私有方法中。
<%= simple_form_for(@clock_entry) do |f| %>
<%= f.error_notification %>
<%= f.error_notification message: f.object.errors[:base].to_sentence if f.object.errors[:base].present? %>
<div class="form-inputs">
<%#= f.association :user %>
<%= f.input :purpose %>
<%#= f.input :time_in %>
<%#= f.input :time_out %>
</div>
<div class="form-actions">
<%= f.button :submit %>
</div>
<% end %>
控制器:
class ClockEntriesController < ApplicationController
def new
@clock_entry = ClockEntry.new
end
def create
@clock_entry = ClockEntry.new(clock_entry_params)
respond_to do |format|
if @clock_entry.save
format.html { redirect_to @clock_entry, notice: 'Clock entry was successfully created.' }
format.json { render :show, status: :created, location: @clock_entry }
else
format.html { render :new }
format.json { render json: @clock_entry.errors, status: :unprocessable_entity }
end
end
end
private
def set_time_in
@clock_entry.time_in = Time.now
end
def set_time_out
@clock_entry.time_in = Time.now
end
def clock_entry_params
params.require(:clock_entry).permit(:user_id, :purpose, :time_in, :time_out)
end
end
任何帮助将不胜感激。注意:正在使用Postgres
答案 0 :(得分:0)
现在,我想我知道在哪里以及为什么会收到此错误。如我所说,我在设置NULL
和time_in
的私有方法中编写了其他函数,这些方法的外观如下:
time_out
首先,不应将业务逻辑功能包含在Controller中。要阅读Business Logic,请选中https://www.reddit.com/r/rails/comments/77eesr/what_is_business_logic/
我如何解决此问题?:
1。将所有业务逻辑方法移至您的模型。所以现在我有:
def set_time_in
@clock_entry.time_in = Time.now
end
def set_time_out
@clock_entry.time_in = Time.now
end
2。然后,您可以从控制器中调用这些功能。所以我有:
class ClockEntry < ApplicationRecord
belongs_to :user
validates :purpose, presence: true
def set_time_in
self.time_in = Time.now
end
def set_time_out
self.time_in = Time.now
end
end
这就是我所做的全部,并且工作正常。我认为有时候阅读您的堆栈内容并用您必须忘记的最小事物来刷新是值得的。我希望这可以帮助别人。 class ClockEntriesController < ApplicationController
def create
@clock_entry = current_user.clock_entries.new(clock_entry_params)
@clock_entry.set_time_in # I am calling those logics here.
respond_to do |format|
if @clock_entry.save
format.html { redirect_to @clock_entry, notice: 'Clock entry was successfully created.' }
format.json { render :show, status: :created, location: @clock_entry }
else
format.html { render :new }
format.json { render json: @clock_entry.errors, status: :unprocessable_entity }
end
end
end
private
def set_clock_entry
@clock_entry = ClockEntry.find(params[:id])
end
def clock_entry_params
params.require(:clock_entry).permit(:user_id, :purpose, :time_in, :time_out)
end
end
。