我已经尝试谷歌，从这个论坛看我的问题的解决方案，但到目前为止没有运气。我想通过单击图片暂停我的CSS3动画（图像幻灯片放映），并通过单击图片恢复到相同的动画。
我知道如何暂停幻灯片放映，我也可以恢复一次，但如果尝试暂停和恢复多次，它就会停止工作。以下是我的代码的样子：
<!DOCTYPE html>
<html>
<head>
<title></title>
<style type="text/css">
.pic {
position: absolute;
opacity: 0;
}
#pic1 {
-webkit-animation: pic1 4s infinite linear;
}
#pic2 {
-webkit-animation: pic2 4s infinite linear;
}
@-webkit-keyframes pic1 {
0% {opacity: 0;}
5% {opacity: 1;}
45% {opacity: 1;}
50% {opacity: 0;}
100% {opacity: 0;}
}
@-webkit-keyframes pic2 {
0% {opacity: 0;}
50% {opacity: 0;}
55% {opacity: 1;}
95% {opacity: 1;}
100% {opacity: 0;}
}
</style>
<script type="text/javascript">
function doStuff(){
var pic1 = document.getElementById("pic1");
var pic2 = document.getElementById("pic2");
pic1.style.webkitAnimationPlayState="paused";
pic2.style.webkitAnimationPlayState="paused";
pic1.onclick = function(){
pic1.style.webkitAnimationPlayState="running";
pic2.style.webkitAnimationPlayState="running";
}
pic2.onclick = function(){
pic1.style.webkitAnimationPlayState="running";
pic2.style.webkitAnimationPlayState="running";
}
}
</script>
</head>
<body>
<img id="pic1" class="pic" src="photo1.jpg" />
<img id="pic2" class="pic" src="photo2.jpg" onclick="doStuff()" />
</body>
</html>
我不想使用任何JS库（例如jQuery）或任何其他外部解决方案。
我的猜测是doStuff函数中的函数仍在运行，这就是为什么pause和resume只能运行一次。
点击一次后有没有办法清除这些功能？或者我是否试图以完全错误的方式做到这一点？感谢帮助。 ：）
答案 0 :(得分：145)
我发现使用css类更容易。有了它，您可以为每个浏览器使用前缀。
.paused{
-webkit-animation-play-state:paused;
-moz-animation-play-state:paused;
-o-animation-play-state:paused;
animation-play-state:paused;
}
然后你只需要在你的动画元素中添加或删除这个类就可以暂停/恢复动画。
答案 1 :(得分：32)
以下是使用javascript的解决方案：
var imgs = document.querySelectorAll('.pic');
for (var i = 0; i < imgs.length; i++) {
imgs[i].onclick = toggleAnimation;
imgs[i].style.webkitAnimationPlayState = 'running';
}
function toggleAnimation() {
var style;
for (var i = 0; i < imgs.length; i++) {
style = imgs[i].style;
if (style.webkitAnimationPlayState === 'running') {
style.webkitAnimationPlayState = 'paused';
document.body.className = 'paused';
} else {
style.webkitAnimationPlayState = 'running';
document.body.className = '';
}
}
}.pic {
position: absolute;
opacity: 0;
}
#pic1 {
-webkit-animation: pic1 4s infinite linear;
}
#pic2 {
-webkit-animation: pic2 4s infinite linear;
}
@-webkit-keyframes pic1 {
0% {
opacity: 0;
}
5% {
opacity: 1;
}
45% {
opacity: 1;
}
50% {
opacity: 0;
}
100% {
opacity: 0;
}
}
@-webkit-keyframes pic2 {
0% {
opacity: 0;
}
50% {
opacity: 0;
}
55% {
opacity: 1;
}
95% {
opacity: 1;
}
100% {
opacity: 0;
}
}
.paused {
background-color: #ddd;
}<img id="pic1" class="pic" src="http://placehold.it/200x200/ff0000/ffffff">
<img id="pic2" class="pic" src="http://placehold.it/200x200/ff00ff/ffffff">
jQuery解决方案（更短，更易读）：
var imgs = $('.pic'),
playState = '-webkit-animation-play-state';
imgs.click(function() {
imgs.css(playState, function(i, v) {
return v === 'paused' ? 'running' : 'paused';
});
$('body').toggleClass('paused', $(this).css(playState) === 'paused');
});.pic {
position: absolute;
opacity: 0;
}
#pic1 {
-webkit-animation: pic1 4s infinite linear;
}
#pic2 {
-webkit-animation: pic2 4s infinite linear;
}
@-webkit-keyframes pic1 {
0% {
opacity: 0;
}
5% {
opacity: 1;
}
45% {
opacity: 1;
}
50% {
opacity: 0;
}
100% {
opacity: 0;
}
}
@-webkit-keyframes pic2 {
0% {
opacity: 0;
}
50% {
opacity: 0;
}
55% {
opacity: 1;
}
95% {
opacity: 1;
}
100% {
opacity: 0;
}
}
.paused {
background-color: #ddd;
}<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<img id="pic1" class="pic" src="http://placehold.it/200x200/ff0000/ffffff">
<img id="pic2" class="pic" src="http://placehold.it/200x200/ff00ff/ffffff">
答案 2 :(得分：7)
这是为了扩展Luis Hijarrubia给出的答案
.pause {
-webkit-animation-play-state: paused !important;
-moz-animation-play-state: paused !important;
-o-animation-play-state: paused !important;
animation-play-state: paused !important;
}
在我的页面中，我从父元素触发了类的更改。我想做的就是旋转图像。但似乎因为我没有使用悬停，添加暂停的类对动画状态没有任何影响。
使用！important确保这些值被新添加的CSS值覆盖。
答案 3 :(得分：1)
var e = document.getElementsById("Your_Id");
e.addEventListener("animationstart", listener, false);
e.addEventListener("animationend", listener, false);
e.addEventListener("animationiteration", listener, false);
function listener(e) { alert("Your POSITION parameter:" + .target.style.position);
switch(e.type) {
case "animationstart":
d = "Started: elapsed time is " + e.elapsedTime;
break;
case "animationend":
d = "Ended: elapsed time is " + e.elapsedTime;
break;
case "animationiteration":
d= "New loop started at time " + e.elapsedTime; alert("pausing for 1 seconddddddd!!!!!!!"); e.target.style.animationPlayState = "paused"; window.setTimeout(function(){e.target.style.animationPlayState = "running";}, 1000);
break;
}
}
答案 4 :(得分：-1)
我还没有测试过它，但也许是这样的？
<!DOCTYPE html>
<html>
<head>
<title></title>
<style type="text/css">
.pic { position: absolute;opacity: 0; }
.pic1 { -webkit-animation: pic1 4s infinite linear; }
.pic2 { -webkit-animation: pic2 4s infinite linear; }
@-webkit-keyframes pic1 { 0% {opacity: 0;}
5% {opacity: 1;}
45% {opacity: 1;}
50% {opacity: 0;}
100% {opacity: 0;} }
@-webkit-keyframes pic2 { 0% {opacity: 0;}
50% {opacity: 0;}
55% {opacity: 1;}
95% {opacity: 1;}
100% {opacity: 0;} }
</style>
<script type="text/javascript">
function doStuff(){
var pic1 = document.getElementById("pic1");
var pic2 = document.getElementById("pic2");
pic1.className="pic paused";
pic2.className="pic paused";
pic1.onclick = function(){
pic1.className="pic pic1";
pic2.className="pic pic2";
}
pic2.onclick = function(){
pic1.className="pic pic1";
pic2.className="pic pic2";
}
}
</script>
</head>
<body>
<img id="pic1" class="pic pic1" src="photo1.jpg" />
<img id="pic2" class="pic pic2" src="photo2.jpg" onclick="doStuff()" />
</body>
</html>