Question

我想做的是从下表中得出马德里（70.89％）和巴塞罗那（83.92％）的结果，并根据“总生产”量对两个结果进行加权

预期结果如下=（70.89％x 52.550 + 83.92 x 135.100）/（52.550 + 135.100）= 80.27％

这是我为建立矩阵表而创建的度量

Total Production = sum(Database[Production])

Total Working Hours = sum(Database[Working Hours])

TotalExpectedProduction = sum(Database[Expected Production])

Avexpectedprod = divide(sumx(Database;[TotalExpectedProduction]*[Total Working Hours]);sum(Database[Working Hours]))

YTD Productivity =
CALCULATE (
    DIVIDE (
        SUMX (
            SUMMARIZE (
                Database;
                Database[Matchine];
                "AA"; [Total Production] / ( [Total Working Hours] * [Avexpectedprod] )
            );
            [AA] * [Total Working Hours]
        );
        [Total Working Hours];
        0
    );
    DATESYTD ( Calendar[Date]; "30/06" );
    FILTER (
        ALL ( 'Calendar' );
        'Calendar'[Date] <= MAX ( 'Calendar'[Date] )
            && 'Calendar'[Fiscal Year] = MAX ( 'Calendar'[Fiscal Year] )
    )
)

这是我的数据表结构 data table 这是矩阵表和预期结果 Image

非常感谢您的支持 RBN

Answer 1

完成！

New2 = 除法（计算（ SUMX（VALUES（Database [Location]）; [YTD Productivity] * [Total Production]）; Database [Location] =“巴塞罗那” || Database [Location] =“马德里” ）; 计算（ SUM（Database [Production]）; Database [Location] =“巴塞罗那” || Database [Location] =“马德里” ））

如何从矩阵表中提取结果值以创建另一个SUMX量度

1 个答案: