我正在尝试构建一个抓取工具,以获取一些学术论文摘要及其相应的标题on this page。
问题是我的for link in bsObj.findAll('a',{'class':'search-track'})
没有返回我进一步构建刮板所需的链接。在我的代码中,检查是这样的:
for link in bsObj.findAll('a',{'class':'search-track'}):
print(link)
上面的for循环确实可以输出任何内容,但是href
链接应位于<a class="search-track" ...</a>
内。
我已经参考了this post,但是更改Beautifulsoup解析器并不能解决我的代码问题。我在Beautifulsoup构造函数"html.parser"
中使用bsObj = bs(html.content, features="html.parser")
。
print(len(bsObj))
和"lxml"
都打印出“ 3”,而"html5lib"
则打印出“ 2”。
此外,我开始使用urllib.request.urlopen
来获取页面,然后尝试使用requests.get()
。不幸的是,这两种方法给了我相同的bsObj
。
这是我编写的代码:
#from urllib.request import urlopen
import requests
from bs4 import BeautifulSoup as bs
import ssl
'''
The elsevier search is kind of a tree structure:
"keyword --> a list of journals (a journal contain many articles) --> lists of articles
'''
address = input("Please type in your keyword: ") #My keyword is catalyst for water splitting
#https://www.elsevier.com/en-xs/search-results?
#query=catalyst%20for%20water%20splitting&labels=journals&page=1
address = address.replace(" ", "%20")
address = "https://www.elsevier.com/en-xs/search-results?query=" + address + "&labels=journals&page=1"
journals = []
articles = []
def getJournals(url):
global journals
#html = urlopen(url)
html = requests.get(url)
bsObj = bs(html.content, features="html.parser")
#print(len(bsObj))
#testFile = open('testFile.txt', 'wb')
#testFile.write(bsObj.text.encode(encoding='utf-8', errors='strict') +'\n'.encode(encoding='utf-8', errors='strict'))
#testFile.close()
for link in bsObj.findAll('a',{'class':'search-track'}):
print(link)
########does not print anything########
'''
if 'href' in link.attrs and link.attrs['href'] not in journals:
newJournal = link.attrs['href']
journals.append(newJournal)
'''
return None
# Ignore SSL certificate errors
ctx = ssl.create_default_context()
ctx.check_hostname = False
ctx.verify_mode = ssl.CERT_NONE
getJournals(address)
print(journals)
谁能告诉我代码中的问题是for循环未打印出任何链接?我需要将期刊的链接存储在列表中,然后访问每个链接以刮取论文摘要。正确的是,论文的摘要部分是免费的,网站不应该因此而阻止我的ID。
答案 0 :(得分:0)
此页面动态加载了jscript,因此Beautifulsoup无法直接处理它。您也许可以使用Selenium来做到这一点,但在这种情况下,您可以通过跟踪页面(for more see, as one of many examples, here.
在您的特定情况下,可以通过以下方式完成:
from bs4 import BeautifulSoup as bs
import requests
import json
#this is where the data is hiding:
url = "https://site-search-api.prod.ecommerce.elsevier.com/search?query=catalyst%20for%20water%20splitting&labels=journals&start=0&limit=10&lang=en-xs"
html = requests.get(url)
soup = bs(html.content, features="html.parser")
data = json.loads(str(soup))#response is in json format so we load it into a dictionary
注意:在这种情况下,也可以完全省去Beautifulsoup并直接加载响应,如data = json.loads(html.content)
中所示。从这一点来看:
hits = data['hits']['hits']#target urls are hidden deep inside nested dictionaries and lists
for hit in hits:
print(hit['_source']['url'])
输出:
https://www.journals.elsevier.com/water-research
https://www.journals.elsevier.com/water-research-x
等