Question

我正在尝试学习Python，但是我陷入了日期/时间例程中，我需要查找在05:00到11:30之间发生的数据，但是无论我怎么做，我都会遇到错误。我认为我需要解码时间，进行数学运算然后编码时间。我确信这是一件简单的事情，但我似乎无法完成。

示例：

riders = [
    ["rider_2391", 37_775370, -122.417571, 37_808601, -122.409807, "17:02:35", "$17.23", "UberX"],
    ["rider_1879", 37.775222, 122.47109, 37.808080, -122.410002, "06:25:08",  "$22.25", "UberX"],
    ["rider_98233", 37.784125, -122.471891, 37.763025, 122.478749, "11:48:55", "$6.28",  "Pool"]
]

def getRiderDate(riders):
    ans = []
    for rider in riders:
        if rider[5] >= "05:00:00" and rider[5] <= "11:30:00":
            ans.insert(len(ans), rider)
    return ans

print(getRiderDate(riders)

Answer 1

您的问题是回路控制错误

   for rider in riders:                
            if rider[5] >= "05:00:00" and rider[5] <= "11:30:00":
                    ans.insert(len(ans), rider)
            return ans;

您检查一名骑手并返回，无论比赛结果如何。试试这个：

def getRiderDate(riders):
    ans = []
    for rider in riders:                    
        if rider[5] >= "05:00:00" and rider[5] <= "11:30:00":
            ans.append(rider)

    return ans;

return会在循环后而不是内部循环。

输出：

[['rider_1879', 37.775222, 122.47109, 37.80808, -122.410002, '06:25:08', '$22.25', 'UberX']]

Answer 2

我将使用datetime模块，主要是时间。还有以前的答案指出了什么（循环内返回ans等）

import datetime

riders = [["rider_2391", 37_775370, -122.417571, 37_808601, -122_409807, "17:02:35", "$17.23", "UberX"],
          ["rider_1879", 37.775222, 122.47109, 37.808080, -122.410002, "06:25:08", "$22.25", "UberX"],
          ["rider_98233", 37.784125, -122.471891, 37.763025, 122.478749, "11:48:55", "$6.28", "Pool"]]


def getRiderDate(riders):
    ans = []
    t1 = datetime.time(hour=5)
    t2 = datetime.time(hour=11, minute=30)
    for rider in riders:
        t = datetime.datetime.strptime(rider[5], '%H:%M:%S').time()

        if t1 <= t <= t2:  # using chained comparison
            ans.insert(len(ans), rider)
    return ans


print(getRiderDate(riders))

计算范围内的时间

2 个答案: