Question

我有5个可变数目的索引列表。第一个是Azimutes列表：

lista_az = ['72', '252'], ['90.9', '270.8'], ['78.4', '258.3'], ['280', '100.3'], ['327.1', '147.1'], ['259.1', '293.8', '79.1', '113.8'], ['126.9', '306.8'], ['205.9', '25.9', '41.5', '221.5'] (...)

Tx列表：

tx = ['8468.00000000 MHz', '8349.00000000 MHz'], ['8349.00000000 MHz', '8468.00000000 MHz'], ['8482.00000000 MHz', '8363.00000000 MHz'], ['8468.00000000 MHz', '8349.00000000 MHz'], ['15.20100000 GHz', '14.78100000 GHz'], ['14.76700000 GHz', '14.80900000 GHz', '15.18700000 GHz', '15.22900000 GHz'], ['1508.50000000 MHz', '1443.00000000 MHz'], ['1450.00000000 MHz', '1515.50000000 MHz', '8468.00000000 MHz', '8349.00000000 MHz'] (...)

Rx列表：

rx = ['8349.00000000 MHz', '8468.00000000 MHz'], ['8468.00000000 MHz', '8349.00000000 MHz'], ['8363.00000000 MHz', '8482.00000000 MHz'], ['8349.00000000 MHz', '8468.00000000 MHz'], ['14.78100000 GHz', '15.20100000 GHz'], ['15.18700000 GHz', '15.22900000 GHz', '14.76700000 GHz', '14.80900000 GHz'], ['1443.00000000 MHz', '1508.50000000 MHz'], ['1515.50000000 MHz', '1450.00000000 MHz', '8349.00000000 MHz', '8468.00000000 MHz'] (...)

极化列表：

pol = ['V', 'V'], ['H', 'H'], ['V', 'V'], ['V', 'V'], ['V', 'V'], ['V', 'V', 'V', 'V'], ['V', 'V'], ['V', 'V', 'V', 'V'] (...)

网络列表：

net = ['1', '1'], ['2', '2'], ['3', '3'], ['4', '4'], ['5', '5'], ['6', '6', '6', '6'], ['7', '7'], ['8', '8', '8', '8']

我正在尝试比较同一列表中的每个元素，以用于Azimute列表：

Azimute(list 1) = 252 - 72 =  180 OK
Azimute(list 2) = 90.9 - 270.8 =~ -180 OK

比较Tx的第一个列表和Rx的第一个列表，

first tx: 8468.00000000 with second Rx: 8468.00000000, and 
second tx with first rx, and so on.

试图找到tx和rx的匹配项（等于值）。

在极化列表中，如果第一个元素等于第二个元素，如果第一个元素等于第三个元素（仅当列表具有此大小时），依此类推。

我尝试这样做：

for lista in range(1, len(lista_az)):
    for x in range(0, len(lista_az[lista])-1):
        try:
            if net[lista][x] == net[lista][x+y]:
                if tx[lista][x] == rx[lista][x+y]:
                    if tx[lista][x+y] == rx[lista][x]:
                        if round(abs(float(lista_az[lista][x]) -float(lista_az[lista][x+y]))) == 180:
                            if pol[lista][x] == pol[lista][x+y]:
                                print("Link of list: ", lista)
                                print("Latitude A: ", lat[lista][x]); 
                                print("Latitude B: ", lat[lista][x+y])
                                print("Longitude A: ", lon[lista][x]); print("Longitude B: ", lon[lista][x + y])
                                print("Height A: ", hei[lista][x]); print("Height B: ", hei[lista][x+y])
        except IndexError:
               value = None

预期输出为（对于所有列表的第一个列表）：

first tx = second rx, 8468.00000000 = 8468.00000000 OK next,
second tx = first rx, 8349.00000000 = 8349.00000000 OK next, 
azimute: 72- 252 = 180 is an link OK next,
polarization of first element is equal of second: V = V OK

好的，这是一个链接，之后我将了解这两个元素的纬度，经度和高度。但是，当循环包含两个以上元素的列表时，它不会打印任何内容。

尝试分析列表列表之间的值

0 个答案: