无论Excel中的日历星期如何,如何获取当天的星期数?
我正在寻找“ nth_week_number”列。在下表中,“ 2/5/2018”将落在2018年2月的第二个星期,但这是该月的第一个星期一。 请有人帮助解决此问题。
| Date | Weekday | week _of_the_month | nth_week_number |
|-----------|-----------|--------------------|-----------------|
| 2/1/2018 | Thursday | 1 | 1st Thrusday |
| 2/2/2018 | Friday | 1 | 1st Friday |
| 2/3/2018 | Saturday | 1 | 1st Saturday |
| 2/4/2018 | Sunday | 2 | 1st Sunday |
| 2/5/2018 | Monday | 2 | 1st Monday |
| 2/6/2018 | Tuesday | 2 | 1st Tuesday |
| 2/7/2018 | Wednesday | 2 | 1st Wednesday |
| 2/8/2018 | Thursday | 2 | 2nd Thrusday |
| 2/9/2018 | Friday | 2 | 2nd Friday |
| 2/10/2018 | Saturday | 2 | 2nd Saturday |
| 2/11/2018 | Sunday | 3 | 2nd Sunday |
| 2/12/2018 | Monday | 3 | 2nd Monday |
| 2/13/2018 | Tuesday | 3 | 2nd Tuesday |
答案 0 :(得分:3)
在第2行中尝试使用此公式并将其复制下来:
=(ROUNDUP(DAY(A1)/7;0)&". "&TEXT(A1;"dddd"))
这将输出2。例如,星期四,将其格式化为1st,2nd,3rd等将需要更多的工作。请注意,您可能必须在英文版的Excel(我认为)中将分号;
更改为常规逗号,
。
编辑:根据@Ron Rosenfeld的建议,更新了公式以适合您的具体情况:
=(CHOOSE(ROUNDUP(DAY(B1)/7;0);"1st ";"2nd "; "3rd "; "4th "; "5th ")&TEXT(B1;"dddd"))