单击按钮而不上传文件

Question

我有一个html表单，用户可以上传文件，但是如果用户直接单击提交按钮而不上传任何文件，django就会出错。我该如何控制这个问题？

upload.html

    <!-- Upload form. Note enctype attribute! -->
    <form method="post" enctype="multipart/form-data" multiple>
        {% csrf_token %}
        <input type= "file" name ="docfile" multiple/>

        <button id="yukle" type="submit" value="Upload">
            <img src="/static/img/upload.png" width=28 height=30 alt="Yükle"/>
        </button>
    </form>

views.py

def SenetList(request):
    if request.method == 'POST':
        form = DocumentForm(request.POST, request.FILES)
        if form.is_valid():
            dosya_tipi = "Senet"
            context = upload(request.FILES.getlist('docfile'),form, dosya_tipi)
            return render(request, 'operations/upload.html', context)
    else:
        form = DocumentForm()
        return render(request, 'operations/upload.html', {'form': form})

forms.py

class DocumentForm(forms.Form):
    docfile = forms.FileField(
        label='Select a file',
        help_text='max. 42 megabytes'
    )

我给出了这样的错误：

  

/ upload / senet处的ValueError

     

视图operation.views.SenetList没有返回HttpResponse对象。它返回None。

Answer 1

如果方法为post且表单无效，则将隐式返回None。这会导致错误。为表单无效的方法发布实施回复