Question

我尝试创建一个用户界面，用户在输入框中输入自己的名字，当我尝试打印名称变量时，PY_VAR被打印出了问题。

import tkinter as tk


class TestApp(tk.Tk):
    def __init__(self):
        tk.Tk.__init__(self)
        self._frame = None
        self.geometry('400x500')
        self.switch_frame(StartPage)

    def switch_frame(self, frame_class):
        """Destroys current frame and replaces it with a new one."""
        new_frame = frame_class(self)
        if self._frame is not None:
            self._frame.destroy()
        self._frame = new_frame
        self._frame.grid()

    def save(self,var1name):
        print(var1name)


class StartPage(tk.Frame):
    def __init__(self, master):
        tk.Frame.__init__(self, master)
        var1name = tk.StringVar()
        #Entry of basic information
        tk.Label(self, text="Please enter setup").grid(row=0, column=1, sticky="W")
        tk.LabelFrame(self, text="labelframe").grid()
        tk.Label(self, text="Name: ").grid(row=1, column=0, sticky="W")
        tk.Entry(self,textvar=var1name).grid(row=1, column=2, sticky="W")

        tk.Button(self, text="Set",
                  command=lambda: master.save(var1name)).grid(row=9, column=1, sticky="E")

        #tk.Button(self, text="Next",
                  #command=lambda: master.switch_frame(PageOne)).grid(row=9, column=2, sticky="E")


if __name__ == "__main__":
    app = TestApp()
    app.mainloop()

我希望在Python界面上打印一个名称，但改为打印PY_VAR

Answer 1

var1name是对Tkinter.StringVar对象的引用。您需要调用其 get方法来访问其表示的值，例如：

print (var1name.get())

get 方法以Python的形式返回变量的当前值。对象。

在您的代码中：

class StartPage(tk.Frame):
    def __init__(self, master):
        tk.Frame.__init__(self, master)
        var1name = tk.StringVar()
        # Entry of basic information
        tk.Label(self, text="Please enter setup").grid(row=0, column=1, sticky="W")
        tk.LabelFrame(self, text="labelframe").grid()
        tk.Label(self, text="Name: ").grid(row=1, column=0, sticky="W")
        tk.Entry(self, textvar=var1name).grid(row=1, column=2, sticky="W")

        tk.Button(self, text="Set",
                  command=lambda: master.save(var1name.get())).grid(row=9, column=1, sticky="E")

如何使用输入框设置变量

1 个答案: