Question

由于我是无数堆栈的新手，因此我试图创建一个用于部署的yml文件（NodeJS lambda函数）。但是我在部署时会发现语法错误。

请在下面的serverless.yml中找到

service: secretManager

provider:
  name: aws
  runtime: nodejs10.x
  timeout: 300
  memorySize: 512
  region: us-east-2
  stage: ${opt:stage,'v1'}
  role: secretManager
  stackTags:
    ApplicationId: ACL_9999999
    Product: secretManager
    Project: secretManager

functions:
  getParams:
    handler: getFromParamStore.getParams
    role: secretManager

resources:
  Resources:
    secretManager:
      Type: AWS::IAM::Role
      Properties:
        Policies:
        - PolicyName: myPolicy
          PolicyDocument:
            Version: '2017'
            Statement:
              - Effect: Allow 
                Action:
                  - logs:CreateLogGroup
                  - logs:CreateLogStream
                  - logs:PutLogEvents
                  - ssm:GetParameters
                  - ssm:GetParameter
                  - ssm:DescribeParameters
                Resource:
                  - 'Fn::Join':
                    - ':'
                    - 'arn:aws:logs'
                    - 'log-group:/aws/lambda/*:*:*'
                    - 'arn:aws:ssm:*:*:parameter/*'

package:
  include:
    - serverless.yml

部署无服务器时抛出错误。

错误：CloudFormation模板无效：模板错误：每个Fn :: Join对象都需要两个参数，（1）字符串定界符和（2）要连接的字符串列表或返回字符串列表的函数（例如Fn :: GetAZs）。

enter image description here

请帮助

Answer 1

正确使用\d的方法是：

Fn::Join

第一个参数resources: Resources: secretManagerLambdaRole: Type: AWS::IAM::Role Properties: Policies: - PolicyName: myPolicy PolicyDocument: Version: '2017' Statement: - Effect: Allow Action: - logs:CreateLogGroup - logs:CreateLogStream - logs:PutLogEvents - ssm:GetParameters - ssm:GetParameter - ssm:DescribeParameters Resource: - 'Fn::Join': - ':' # delimiter - - 'arn:aws:logs' - 'log-group:/aws/lambda/*:*:*' - 'arn:aws:ssm:*:*:parameter/*'是分隔符，第二个参数是要连接的字符串的列表。

无服务器：部署时无服务器错误

1 个答案: