通过id帮助进行XML解析

时间:2011-04-27 05:49:54

标签: php xml xml-parsing

XML新手,不知道我在做什么。我需要一个很好解释,简单的方法来做到这一点。

在上一页中,我使用查询字符串来获取一个id示例:test.php?id = AT

我需要在他们选择的部门中显示所有员工姓名。下面是我的XML文档的片段。

<SOT>
    <DEPARTMENT name="Aviation Technology" id="AT">
        <EMPLOYEE type="Faculty">
            <LOGIN>bdbowen</LOGIN>
            <PASSWORD>bdbowen</PASSWORD>
            <NAME>John J. Doe</NAME>
            <IMAGE>images/faculty/bdbown.jpg</IMAGE>
            <OFFICE>Knoy</OFFICE>
            <PHONE>765.494.2884</PHONE>
            <EMAIL>dsgriggs@purdue.edu</EMAIL>
        </EMPLOYEE>
        <EMPLOYEE type="Faculty">
            <LOGIN>bdbowen</LOGIN>
            <PASSWORD>bdbowen</PASSWORD>
            <NAME>Jill J. Doe</NAME>
            <IMAGE>images/faculty/bdbown.jpg</IMAGE>
            <OFFICE>Knoy</OFFICE>
            <PHONE>765.494.2884</PHONE>
            <EMAIL>dsgriggs@purdue.edu</EMAIL>
        </EMPLOYEE>
    </DEPARTMENT>
    <DEPARTMENT name="Mechanical Engineering Technology" id="MET">
        <EMPLOYEE type="Faculty">
            <LOGIN>bdbowen</LOGIN>
            <PASSWORD>bdbowen</PASSWORD>
            <NAME>John J. Doe</NAME>
            <IMAGE>images/faculty/bdbown.jpg</IMAGE>
            <OFFICE>Knoy</OFFICE>
            <PHONE>765.494.2884</PHONE>
            <EMAIL>dsgriggs@purdue.edu</EMAIL>
        </EMPLOYEE>
    </DEPARTMENT>
</SOT>

例如,如果他们选择使用GET来拉入AT id的链接,我想在页面上显示以下内容:

  

John J. Doe
Jill J. Doe

同样,我不知道我在这里做什么,所以任何帮助都会非常感激。


我尝试了以下代码,但它只显示每个部门的名字。知道如何修改它以显示部门内的所有名称吗?

<script type="text/javascript">
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.open("GET","faculty1.xml",false);
xmlhttp.send();
xmlDoc=xmlhttp.responseXML; 

document.write("<table border='1'>");
var x=xmlDoc.getElementsByTagName("DEPARTMENT");
for (i=0;i<x.length;i++)
  { 
  document.write("<tr><td>");
  document.write(x[i].getElementsByTagName("NAME")[0].childNodes[0].nodeValue);
  document.write("</td></tr>");
  }
document.write("</table>");
</script>

2 个答案:

答案 0 :(得分:1)

您可以使用xpath表达式:

请参阅:https://github.com/homer6/altumo/blob/master/source/php/Xml/XmlElement.md

$xml = <<<XML
<SOT>
    <DEPARTMENT name="Aviation Technology" id="AT">
        <EMPLOYEE type="Faculty">
            <LOGIN>bdbowen</LOGIN>
            <PASSWORD>bdbowen</PASSWORD>
            <NAME>John J. Doe</NAME>
            <IMAGE>images/faculty/bdbown.jpg</IMAGE>
            <OFFICE>Knoy</OFFICE>
            <PHONE>765.494.2884</PHONE>
            <EMAIL>dsgriggs@purdue.edu</EMAIL>
        </EMPLOYEE>
        <EMPLOYEE type="Faculty">
            <LOGIN>bdbowen</LOGIN>
            <PASSWORD>bdbowen</PASSWORD>
            <NAME>Jill J. Doe</NAME>
            <IMAGE>images/faculty/bdbown.jpg</IMAGE>
            <OFFICE>Knoy</OFFICE>
            <PHONE>765.494.2884</PHONE>
            <EMAIL>dsgriggs@purdue.edu</EMAIL>
        </EMPLOYEE>
    </DEPARTMENT>
    <DEPARTMENT name="Mechanical Engineering Technology" id="MET">
        <EMPLOYEE type="Faculty">
            <LOGIN>bdbowen</LOGIN>
            <PASSWORD>bdbowen</PASSWORD>
            <NAME>John J. Doe</NAME>
            <IMAGE>images/faculty/bdbown.jpg</IMAGE>
            <OFFICE>Knoy</OFFICE>
            <PHONE>765.494.2884</PHONE>
            <EMAIL>dsgriggs@purdue.edu</EMAIL>
        </EMPLOYEE>
    </DEPARTMENT>
</SOT>
XML;

$xml_element = new \Altumo\Xml\XmlElement($xml);
$results = $xml_element->queryWithXpath( 'DEPARTMENT[@id="AT"]/EMPLOYEE/NAME' );
var_dump( $results );


array(2) {
  [0]=>
  string(11) "John J. Doe"
  [1]=>
  string(11) "Jill J. Doe"
}

答案 1 :(得分:1)

编辑:从Gordon获得一些提示后,这是我编辑过的代码:

$xmlObject = smplexml_load_file("staff.xml");
$id = $_GET["id"];
$employees = null;

foreach($xmlObject as $key => $value){
    $attributes = $xmlObject[0]->DEPARTMENT->attributes();
    if($attributes["id"] == $id){
        $employees = $xmlObject[0]->DEPARTMENT->EMPLOYEE;
        break;
    }
}

foreach($employees as $key => $value){
    print $value->NAME . "\n";
}

基本上,您将获得$ employees变量中的雇员列表,您可以迭代并按照您的要求检索名称。