Question

“我正在做一个指标。我希望能够对其进行回测。”

“这是我已经尝试过的”

fromDay   = input(defval= 1, title="fromDay",minval= 1, maxval= 31)
fromMonth = input(defval= 1, title="fromMonth",minval= 1, maxval= 12)
fromYear  = input(defval= 1, title="fromYear",minval= 1017)

toDay     = 1 //input(defval= 1, title="toDay",minval= 1, maxval= 31)
toMonth   = 1 //input(defval= 1, title="toMonth",minval=1, maxval= 31)
toYear    = 9999 //input(defval= 9999, title="toYear",minval= 9999)

Start     = timestamp(fromDay , FromMonth , fromYear , 00 , 00) //start 
of window
Finish    = timestamp(toDay , toMonth , toYear , 00 , 00)       //end 
of window
Window()  => time => Start and time <= Finish ? true : false //create 
the function "within the window of time"

“这是我得到的错误信息。输入=>时出现语法错误。我在Window（）函数中遇到了错误”

Answer 1

只需重复使用工作代码即可，您将在这里找到：http://www.pinecoders.com/faq_and_code/#how-do-i-implement-date-range-filtering-in-strategies

使用此功能时，它还为您提供了更大的灵活性。

如果您真的想使用代码，这是正确的语法：

//@version=4
study("My Script")
fromDay   = input(defval= 1, title="fromDay",minval= 1, maxval= 31)
fromMonth = input(defval= 1, title="fromMonth",minval= 1, maxval= 12)
fromYear  = input(defval= 1017, title="fromYear",minval= 1017)

toDay     = 1 //input(defval= 1, title="toDay",minval= 1, maxval= 31)
toMonth   = 1 //input(defval= 1, title="toMonth",minval=1, maxval= 31)
toYear    = 9999 //input(defval= 9999, title="toYear",minval= 9999)

Start     = timestamp(fromYear , fromMonth , fromDay , 00 , 00) //start  of window
Finish    = timestamp(toYear , toMonth , toDay , 00 , 00)       //end  of window
Window()  => time >= Start and time <= Finish ? true : false //create the function "within the window of time"

plot(Window()?1:0)

回测时间码有问题

1 个答案: