使用jsxgraph的setjessiecode

Question

使用setjessie中的jsxgraph处理角度标签。是否有任何setjessiecode属性可以用来处理这种情况。

Answer 1

不确定，如果我理解正确的问题。特别是，我不知道方法private string getPath() { #if UNITY_EDITOR return Application.streamingAssetsPath; #elif UNITY_ANDROID return Application.persistentDataPath; #elif UNITY_STANDALONE_WIN return Application.streamingAssetsPath; #else return ""; #endif } private string[] loadExternal_Question(int qIndex) { Debug.Log("External File: " + getPath() + "/Quiz/Q" + qIndex + ".txt"); string[] q_Data = File.ReadAllLines(getPath() + "/Quiz/Q" + qIndex + ".txt"); QuestionTitle_LB.text = q_Data[0].Replace("//n", "\n"); Answer_1.text = q_Data[1].Replace("//n", "\n"); Answer_2.text = q_Data[2].Replace("//n", "\n"); Answer_3.text = q_Data[3].Replace("//n", "\n"); Answer_4.text = q_Data[4].Replace("//n", "\n"); CurrentQ = int.Parse(q_Data[5]); FeedBack_LB.text = q_Data[6].Replace("//n", "\n"); return q_Data; } 。但这是一个示例，如何显示角度值而不是其名称：

private void Label_Click(object sender, EventArgs e)
{
  var nameLabel = ( sender as Label )?.Name ?? "Error";
  // ...
}

private void Label_Enter(object sender, EventArgs e)
{
  ( sender as Label ).Cursor = Cursors.Hand;
}

private void Label_Leave(object sender, EventArgs e)
{
  ( sender as Label ).Cursor = Cursors.Default;
}

在https://jsfiddle.net/yj7mhvk1/上查看它的运行情况