我有一张表格，其中包含以下数据：
ID |start_date |end_date |amount
---|------------|-----------|--------
1 |2019-03-21 |2019-05-09 |10000.00
2 |2019-04-02 |2019-04-10 |30000.00
3 |2018-11-01 |2019-01-08 |20000.00
我希望以年/月为基础，以正确的计算量取回拆分的记录。
我希望结果是这样的：
ID |month |year |amount
---|------|-------|--------
1 |3 | 2019 | 2200.00
1 |4 | 2019 | 6000.00
1 |5 | 2019 | 1800.00
2 |4 | 2019 |30000.00
3 |11 | 2018 | 8695.65
3 |12 | 2018 | 8985.51
3 |1 | 2019 | 2318.84
实现此目标的最佳方法是什么？我认为您必须使用DATEDIFF来获取start_date和end_date之间的天数，以计算每天的金额，但是我不确定如何将其作为每月/每年的记录返回。
提前Tnx！
答案 0 :(得分：2)
这是一个主意。我使用Tally来为每天创建与该Amount相关的金额的一天。然后，我将CREATE TABLE dbo.YourTable(ID int,
StartDate date,
EndDate date,
Amount decimal(12,2));
GO
INSERT INTO dbo.YourTable (ID,
StartDate,
EndDate,
Amount)
VALUES(1,'2019-03-21','2019-05-09',10000.00),
(2,'2019-04-02','2019-04-10',30000.00),
(3,'2018-11-01','2019-01-08',20000.00);
GO
--Create a tally
WITH N AS(
SELECT N
FROM (VALUES(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL),(NULL))N(N)),
Tally AS(
SELECT TOP (SELECT MAX(DATEDIFF(DAY, t.StartDate, t.EndDate)+1) FROM dbo.YourTable t) --Limits the rows, might be needed in a large dataset, might not be, remove as required
ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) -1 AS I
FROM N N1, N N2, N N3), --1000 days, is that enough?
--Create the dates
Dates AS(
SELECT YT.ID,
DATEADD(DAY, T.I, YT.StartDate) AS [Date],
YT.Amount,
COUNT(T.I) OVER (PARTITION BY YT.ID) AS [Days]
FROM Tally T
JOIN dbo.YourTable YT ON T.I <= DATEDIFF(DAY, YT.StartDate, YT.EndDate))
--And now aggregate
SELECT D.ID,
DATEPART(MONTH,D.[Date]) AS [Month],
DATEPART(YEAR,D.[Date]) AS [Year],
CONVERT(decimal(12,2),SUM(D.Amount / D.[Days])) AS Amount
FROM Dates D
GROUP BY D.ID,
DATEPART(MONTH,D.[Date]),
DATEPART(YEAR,D.[Date])
ORDER BY D.ID,
[Year],
[Month];
GO
DROP TABLE dbo.YourTable;
GO
的值除以天数，然后按天和年分组：
ID, TESTA, RESULTA, UNITA, TESTB, RESULTB, UNITB, OTHER_UNITB
1, 'T1', 10, 1, 'T2', 2.5, , 'kg',
2, 'T1', 15, 1, 'T2', 1.5, 1, ,
3, 'T1', , , 'T2', 1, 1,