我有类似的方法:
static List<Employee> getEmployeesByFactoryAndTask(
ProtectedMap<String, Factory> factoryMap, String factoryName, Task task) {
return factoryMap.values().stream()
.filter(factory -> factory.getName().equals(factoryName))
.map(Factory::getEmployees)
.flatMap(Optional::stream)
.flatMap(Collection::stream)
.filter(employee -> employee.getTask().equals(task))
.collect(Collectors.toList());
}
假定通过Employees
和factoryName
枚举参数过滤Task
集合。
上面的代码可以正常工作,但是我想在我的ProtectedMap类中使用辅助方法find
,
public class ProtectedMap<T, U> extends HashMap<T, U> {
public Optional<U> find(T key) {
return Optional.ofNullable(super.get(key));
}
}
以获得相同的结果。
到目前为止,我的方法如下:
return factoryMap
.find(factoryName)
.stream()
.map(Factory::getEmployees)
.flatMap(Optional::stream)
.flatMap(Collection::stream)
.collect(Collectors.toMap(Employee::getTask, Function.identity()));
但是我不知道该在第二个方法调用find
中放置Task
进行过滤以达到绝望效果。另外,Factory包含两个字段:Optional<List<Employees>>
和String
,这是factory的名称。
对于如何解决问题,我将不胜感激。
答案 0 :(得分:0)
下面是处理您的要求的代码,但是getEmployeesByFactoryAndTask
还返回Optional<List<Employee>>
,据我所知,此返回值可以由您处理。
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Optional;
import java.util.stream.Collector;
import java.util.stream.Collectors;
import static java.util.stream.Collectors.*;
enum Task {
QA, DEVELOPEMENT, DESIGN
}
class Employee {
long id;
String name;
Task task;
Employee(long id, String name, Task task) {
this.id = id;
this.name = name;
this.task = task;
}
Task getTask() {
return task;
}
}
class Factory {
List<Employee> employees;
Factory() {}
Factory(List<Employee> employees) {
this.employees = employees;
}
public Optional<List<Employee>> getEmployees() {
return Optional.ofNullable(employees);
}
}
class ProtectedMap<T, U> extends HashMap<T, U> {
public Optional<U> find(T key) {
return Optional.ofNullable(super.get(key));
}
}
public class Main57989215 {
public static void main(String[] args) {
List<Employee> employees1 = new ArrayList<>();
employees1.add(new Employee(21, "Alen", Task.DESIGN));
employees1.add(new Employee(31, "Herry", Task.QA));
employees1.add(new Employee(41, "John", Task.DEVELOPEMENT));
employees1.add(new Employee(51, "Martin", Task.QA));
employees1.add(new Employee(61, "Jack", Task.DESIGN));
List<Employee> employees2 = new ArrayList<>();
employees2.add(new Employee(121, "John", Task.DESIGN));
employees2.add(new Employee(131, "Porter", Task.QA));
employees2.add(new Employee(141, "Cena", Task.DEVELOPEMENT));
employees2.add(new Employee(151, "Luther", Task.QA));
employees2.add(new Employee(161, "Dinga", Task.DESIGN));
ProtectedMap<String, Factory> factoryMap = new ProtectedMap<>();
factoryMap.put("factory1", new Factory(employees1));
factoryMap.put("factory2", new Factory(employees2));
factoryMap.put("factory3", new Factory());
System.out.println(getEmployeesByFactoryAndTask(factoryMap, "factory1", Task.QA));
System.out.println(getEmployeesByFactoryAndTask(factoryMap, "factory1", Task.QA));
System.out.println(getEmployeesByFactoryAndTask(factoryMap, "factory2", Task.DEVELOPEMENT));
System.out.println(getEmployeesByFactoryAndTask(factoryMap, "factory3", Task.DESIGN));
System.out.println(getEmployeesByFactoryAndTask(factoryMap, "factory4", Task.QA));
}
static Optional<List<Employee>> getEmployeesByFactoryAndTask(ProtectedMap<String, Factory> factoryMap, String factoryName, Task task) {
return Optional.ofNullable(factoryMap.find(factoryName)).orElse(Optional.empty())
.flatMap(factory -> Optional.ofNullable(factory.getEmployees())
.orElse(Optional.empty()).map(employees -> employees.stream()
.filter(employee -> employee.getTask().equals(task)).collect(Collectors.toList())));
}
}