我的自动ID已经在运行。但是,我尝试了手动ID代码并在我的数据库中插入值。我的问题是我如何获得手册ID的值。是的,这很简单,但不是只读。
请检查我的代码:
删除 - 工作正常!
CMSInsurance oInsuranceDelete = new CMSInsurance();
Insurance oInsurance = new Insurance();
List<InsuranceLabel> lstName = oInsuranceDelete.RetrieveInsuranceList();
foreach (InsuranceLabel item in lstName)
{
var code = e.CommandArgument;
if (item.InsuranceCode.ID == code.ToString())
{
oInsurance.InsuranceCode = item.InsuranceCode; //proper getting the value of Insurance Code instead of txtCode.text or e.CommandArgument
oInsuranceDelete.DeleteInsurance(oInsurance);
bind();
}
}
插入自动ID代码 - 正常工作!
oInsurance.Name = txtName.text // for string
CMSInsurance oCMSInsurance = new CMSnsurance();
oCMSInsurance.CreateInsurance(oInsurance);
插入手动识别码 - 不工作..
//Get the Manual value of Insurance Code
//For Insert a New Insurance
CMSInsurance oCMSInsuranceManual= new CMSInsurance ();
List<InsuranceLabel> lstList = oCMSInsuranceManual.RetrieveInsuranceList();
foreach (InsuranceLabel item in lstList)
{
if (item.InsuranceCode.ID != Session["AutoCode"])
{
oInsurance.InsuranceCode = item.InsuranceCode; // I can't insert a string like txtCode.. is there anyway to solve this issue?
}
}
谢谢!
答案 0 :(得分:0)
与tSQL一样,SQL Anywhere不会“通常”允许插入标识字段:
上找到有关SQL的更多信息SQL Server不允许INSERT进入 身份列除非 identity_insert选项设置为on