数组作为函数参数c到c#confusion

时间:2011-04-26 22:50:21

标签: c# c arrays function pinvoke

我正在尝试用C#编写一个类来使用dll中的导出但是我遇到了 一堆函数有一个数组作为函数参数,我不确定 如何处理。以下是一个例子。

我如何在C#函数中使用它?具体如何处理iymdf []?

调用该函数时发生了什么?

这看起来是否正确?

[DllImport("libsofa.dll")]
public static extern int iauJdcalf(int ndp, double dj1, double dj2, ref int[] iymdf =       new int[4]);

示例:

int __stdcall iauJdcalf(int ndp, double dj1, double dj2, int iymdf[4])
{
    int j, js;
    double denom, d1, d2, f1, f2, f;

    /* Denominator of fraction (e.g. 100 for 2 decimal places). */
    if ((ndp >= 0) && (ndp <= 9)) {
        j = 0;
        denom = pow(10.0, ndp);
    } else {
        j = 1;
        denom = 1.0;
    }

    /* Copy the date, big then small, and realign to midnight. */
    if (dj1 >= dj2) {
        d1 = dj1;
        d2 = dj2;
    } else {
        d1 = dj2;
        d2 = dj1;
    }
    d2 -= 0.5;

    /* Separate days and fractions. */
    f1 = fmod(d1, 1.0);
    f2 = fmod(d2, 1.0);
    d1 = floor(d1 - f1);
    d2 = floor(d2 - f2);

    /* Round the total fraction to the specified number of places. */
    f = floor((f1+f2)*denom + 0.5) / denom;

    /* Re-assemble the rounded date and re-align to noon. */
    d2 += f + 0.5;

    /* Convert to Gregorian calendar. */
    js = iauJd2cal(d1, d2, &iymdf[0], &iymdf[1], &iymdf[2], &f);
    if (js == 0) {
        iymdf[3] = (int) (f * denom);
    } else {
        j = js;
    }

    /* Return the status. */
    return j;
} 

功能文档:

/*
**  - - - - - - - - - -
**   i a u J d c a l f
**  - - - - - - - - - -
**
**  Julian Date to Gregorian Calendar, expressed in a form convenient
**  for formatting messages:  rounded to a specified precision.
**
**  This function is part of the International Astronomical Union's
**  SOFA (Standards Of Fundamental Astronomy) software collection.
**
**  Status:  support function.
**
**  Given:
**     ndp       int      number of decimal places of days in fraction 
**     dj1,dj2   double   dj1+dj2 = Julian Date (Note 1)
**
**  Returned:
**     iymdf     int[4]   year, month, day, fraction in Gregorian
**                        calendar
**
**  Returned (function value):
**               int      status:
**                          -1 = date out of range
**                           0 = OK
**                          +1 = NDP not 0-9 (interpreted as 0)
**
**  Notes:
**
**  1) The Julian Date is apportioned in any convenient way between
**     the arguments dj1 and dj2.  For example, JD=2450123.7 could
**     be expressed in any of these ways, among others:
**
**             dj1            dj2
**
**         2450123.7           0.0       (JD method)
**         2451545.0       -1421.3       (J2000 method)
**         2400000.5       50123.2       (MJD method)
**         2450123.5           0.2       (date & time method)
**
**  2) In early eras the conversion is from the "Proleptic Gregorian
**     Calendar";  no account is taken of the date(s) of adoption of
**     the Gregorian Calendar, nor is the AD/BC numbering convention
**     observed.
**
**  3) Refer to the function iauJd2cal.
**
**  4) NDP should be 4 or less if internal overflows are to be
**     avoided on machines which use 16-bit integers.
**
**  Called:
**     iauJd2cal    JD to Gregorian calendar
**
**  Reference:
** 
**     Explanatory Supplement to the Astronomical Almanac,
**     P. Kenneth Seidelmann (ed), University Science Books (1992),
**     Section 12.92 (p604).
**
**  This revision:  2010 July 27
**
**  SOFA release 2010-12-01
**
**  Copyright (C) 2010 IAU SOFA Board.  See notes at end.
*/

3 个答案:

答案 0 :(得分:4)

从C#声明中删除 ref 关键字,这是不正确的。您还需要丢失声明中的初始化,这是不支持的语法。在拨打电话之前初始化阵列。

[DllImport("libsofa.dll")]
public static extern int iauJdcalf(int ndp, double dj1, double dj2, int[] iymdf);
...
    int[] arr = new int[] { 1, 2, 3, 4 };
    int retval = iauJdcalf(1, 2, 3, arr);

答案 1 :(得分:1)

您将需要标准函数调用,具体取决于您正在执行的操作。函数定义只是简单地说“这些是我的输入”,然后当你调用它时,你必须提供实际值。您不会重新创建函数def。

[DllImport("libsofa.dll")]
myReturn = iauJdcalf(1, 2.0, 2.0, [1,2,3,4]);

你的函数定义为返回一个int,所以我们用myReturn变量捕获它,你当然需要首先声明它。然后我们提供一个int,两个双精度数组和一个数组。您还可以传递这些类型的变量,小心确保您的数组与所需的大小相同。

另外,注意你的指针!如果将变量传递给c,它会复制到函数中定义的局部变量。如果你给它一个指针,你需要在函数定义中声明它,并意识到我们现在正在玩指针游戏。

答案 2 :(得分:0)

太回答我自己的问题,我认为会涉及更多的Marshaling东西,但是 下面的代码给出了合理的输出。

    [DllImport("libsofa.dll")]
    public static extern int iauJdcalf(int ndp, double dj1, double dj2,    [MarshalAs(UnmanagedType.LPArray, SizeConst = 4)] int[] iymdf);

以及:

    [DllImport("libsofa.dll")]
    public static extern int iauJdcalf(int ndp, double dj1, double dj2, int[] iymdf);