Question

我有：

 Table A
 -------
 N0       Date        Time
 -----------------------------
 123    20-Apr-11      10:00:05
 123    20-Apr-11      10:00:06
 456    20-Apr-11      10:00:01
 456    20-Apr-11      10:00:02

 Table B
 -------
 N0       Date        Time
 -----------------------------
 123    20-Apr-11      10:00:02
 123    20-Apr-11      10:00:04
 123    20-Apr-11      10:00:05
 123    20-Apr-11      10:00:07
 123    20-Apr-11      10:00:08
 456    20-Apr-11      10:00:04
 456    20-Apr-11      10:00:05
 456    20-Apr-11      10:00:02
 456    20-Apr-11      10:00:03
 456    20-Apr-11      10:00:00

期望结果

 A.N0     A.Date       A.Time     B.Time
 ----------------------------------------
 123    20-Apr-11      10:00:05  10:00:07   
 123    20-Apr-11      10:00:06  10:00:08
 456    20-Apr-11      10:00:01  10:00:03
 456    20-Apr-11      10:00:02  10:00:04

注意

如果您看到上述结果，则B.time应大于A.time且不应重复加入。

请建议我如何使用oracle SQL语句执行此操作。

Answer 1

以下内容可以为您提供所需的输出：

With NumberedA As
    (
    Select *
        , Row_Number() Over ( Partition By N0, Date Order By Time ) Num
    From TableA
    )
    , NumberedB As
    (
    Select A.N0, A.Date
        , A.Time ATime
        , B.Time BTime
        , Row_Number() Over ( Partition By A.N0, A.Date, A.Time Order By B.Time ) Num
    From TableA A
        Join TableB B
            On B.N0 = A.N0
                And B.Date = A.Date
                And B.Time > A.Time
    )
Select A.N0, A.Date, A.Time, B.Time
From NumberedA A
    Join NumberedB B
        On B.N0 = A.N0
            And B.Date = A.Date
            And B.ATime = A.Time
            And B.Num = A.Num

那就是说，如果我们理解你的请求背后的推理，那将会有所帮助。

Answer 2

看看这个

但需要在表B中创建一个名为“Flag”的新列

CREATE OR REPLACE PROCEDURE Proc_test
IS
BEGIN
   FOR i IN (SELECT   *
                 FROM a
             ORDER BY NAME, date, time)
   LOOP
      FOR j IN (SELECT   *
                    FROM b
                ORDER BY NAME, date, time)
      LOOP
         IF     i.NAME = j.NAME
            AND i.date = j.date
            AND j.flag IS NULL
            AND i.time < j.time
         THEN
            INSERT INTO target
                        (NAME, date, time1, time2
                        )
                 VALUES (i.NAME, i.date, i.time, j.time
                        );

            UPDATE b
               SET flag = 'Y'
             WHERE NAME = i.NAME AND date = i.date AND time = j.time;

            COMMIT;
         END IF;
      END LOOP;
   END LOOP;
END;
/

工作正常......

Oracle - 如何根据以下逻辑选择记录？

期望结果

注意

2 个答案: