Question

当我创建一个简单的触发器并将其分配给调度程序时，它会立即触发，然后在预定的时间间隔再次触发。怎么才能在指定时间点火？

以下示例代码：

// construct a scheduler factory
ISchedulerFactory schedFact = new StdSchedulerFactory();

// get a scheduler
IScheduler sched = schedFact.GetScheduler();            

// construct job info
JobDetail jobDetail = new JobDetail("myJob", "Default", typeof(DumbJob));

// Example trigger to fire after 1 minute, no repeat
Trigger trigger = TriggerUtils.MakeMinutelyTrigger(1, 0);

// Schedule the job
trigger.Name = "demoTrigger";
sched.ScheduleJob(jobDetail, trigger);                       

sched.Start();  

public class DumbJob : IJob
{
   public DumbJob()
   {
   }

    public void Execute(JobExecutionContext context)
    {
        MessageBox.Show("Dumb job is running");
    }
}

Answer 1

触发器对象具有StartTimeUtc属性，您可以使用该属性指定触发器何时开始触发，依此类推。这是一个例子：

     trigger.StartTimeUtc = TriggerUtils.GetEvenMinuteDate(DateTime.Now.AddMinutes(1));

这会创建一个触发器，开始触发下一个偶数分钟。

防止立即触发Quartz.Net事件

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