Question

我有一个带有简单脚本任务的YAML构建管道，该脚本任务根据要构建的分支来设置构建配置：

- script: |
    echo Current branch is %BUILD_SOURCEBRANCHNAME%
    if %BUILD_SOURCEBRANCHNAME% == "master" (
        SET BUILD_CONFIG=Release
    ) else (
        SET BUILD_CONFIG=Debug
    )
    echo ##vso[task.setvariable variable=BuildConfiguration]%BUILD_CONFIG%
    echo BuildConfiguration set to '%BUILD_CONFIG%'

这可以正常工作，但是任务在列表中显示为“ CmdLine”，我想要一些更具描述性的内容。 MS文档中的example表示我应该能够在最后添加一个displayName条目：

- script: |
    echo Current branch is %BUILD_SOURCEBRANCHNAME%
    if %BUILD_SOURCEBRANCHNAME% == "master" (
        SET BUILD_CONFIG=Release
    ) else (
        SET BUILD_CONFIG=Debug
    )
    echo ##vso[task.setvariable variable=BuildConfiguration]%BUILD_CONFIG%
    echo BuildConfiguration set to '%BUILD_CONFIG%'
    displayName: 'Determine Build Configuration'

但是，此操作失败，出现'displayName:' is not recognized as an internal or external command, operable program or batch file.

这很简单，但是我已经尝试了所有我能想到的并且无法正常工作！

Answer 1

修复缩进：

- script: |
    echo Current branch is %BUILD_SOURCEBRANCHNAME%
    if %BUILD_SOURCEBRANCHNAME% == "master" (
        SET BUILD_CONFIG=Release
    ) else (
        SET BUILD_CONFIG=Debug
    )
    echo ##vso[task.setvariable variable=BuildConfiguration]%BUILD_CONFIG%
    echo BuildConfiguration set to '%BUILD_CONFIG%'
  displayName: 'Determine Build Configuration'

Azure DevOps YAML构建管道-设置脚本任务名称

1 个答案: