Question

我想对“ zero：PosNo”进行分组如果删除组命令，它将返回结果，但显然返回以下结果：

INSERT INTO RAPP_ADM.MTO_POS_IMP_TAB (PROJECT_NO, MTO_OWNER_NO, POS_NO, PART_NO, DESCRIPTION, QTY, UNIT, TOT_LEN, TOT_WEIGHT, DRAWING, GRADE, TRACE, BI_PRODUCT, SURFACE, CALC, DISCIPLINE, MADE_BY, POS_NO2, PLT_SEQ, OBJECT_SQ, OBJECT_REVISION) 
VALUES ('6111', '26-0008-R552-MOD-01-M', '1','PIP03D1160', 'PIPE sch.160 ASTM A790 UNS S31', 2.000, 'M', 2.000, 42.700, 'C097-RWP-L-XN-0057-01', 'sch.160 ASTM A790 UNS S31', 'N', '26-0008-R552-MOD-01-1', 0.559, 'N', 'L', 'sindre.thompson', '', 721, '1556750', '1');

INSERT INTO RAPP_ADM.MTO_POS_IMP_TAB (PROJECT_NO, MTO_OWNER_NO, POS_NO, PART_NO, DESCRIPTION, QTY, UNIT, TOT_LEN, TOT_WEIGHT, DRAWING, GRADE, TRACE, BI_PRODUCT, SURFACE, CALC, DISCIPLINE, MADE_BY, POS_NO2, PLT_SEQ, OBJECT_SQ, OBJECT_REVISION) VALUES 
('6111', '26-0008-R552-MOD-01-M', '1','PIP03D1160', 'PIPE sch.160 ASTM A790 UNS S31', 0.660, 'M', 0.660, 14.093, 'C097-RWP-L-XN-0057-01', 'sch.160 ASTM A790 UNS S31', 'N', '26-0008-R552-MOD-01-1', 0.184, 'N', 'L', 'sindre.thompson', '', 721, '1556750', '1');

xmlns:zero="rosenbergverft.com:3D/2011/Zero"

   <xsl:output method="text" omit-xml-declaration="yes" standalone="no" media-type="text/plain"/>
   <xsl:template match="/">
 
<xsl:for-each select="/zero:Zero/zero:MTOOwner/zero:DocumentNo/zero:BiProduct/zero:Part">
<xsl:for-each-group select="/" group-by="zero:POS_NO">
<xsl:sort select="zero:PosNo" />
INSERT INTO RAPP_ADM.MTO_POS_IMP_TAB (PROJECT_NO, MTO_OWNER_NO, POS_NO, PART_NO, DESCRIPTION, QTY, UNIT, TOT_LEN, TOT_WEIGHT, DRAWING, GRADE, TRACE, BI_PRODUCT, SURFACE, CALC, DISCIPLINE, MADE_BY, POS_NO2, PLT_SEQ, OBJECT_SQ, OBJECT_REVISION) VALUES ('
<xsl:value-of select="../../../../pdms:PDMSProject/pdms:ProjectNumber/@text" />', 
'<xsl:value-of select="zero:MtoOwnerNo" />', 
'<xsl:value-of select="zero:PosNo" />',
'<xsl:value-of select="zero:StockNo" />', 
'<xsl:value-of select="zero:Description" />', 
<xsl:choose>
  <xsl:when test="zero:Quantity/@unit = 'mm2'"><xsl:value-of select="format-number(zero:Quantity/@number div 1000000, '#0.000')"/><xsl:text>, 'M2'</xsl:text></xsl:when>
  <xsl:when test="zero:Quantity/@unit = 'mm'"><xsl:value-of select="format-number(zero:Quantity/@number div 1000, '#0.000')"/><xsl:text>, 'M'</xsl:text></xsl:when>
  <xsl:when test="zero:Quantity/@unit = 'pcs'"><xsl:value-of select="format-number(zero:Quantity/@number, '#0')"/><xsl:text>, 'EA'</xsl:text></xsl:when>
  <xsl:otherwise><xsl:value-of select="format-number(zero:Quantity/@number, '#0.000')"/><xsl:text>, ''</xsl:text></xsl:otherwise>
</xsl:choose>, 
<xsl:value-of select="format-number(zero:TotalLength/@number div 1000, '#0.000')" />, 
<xsl:value-of select="zero:TotalWeight/@number" />, 
'<xsl:value-of select="zero:DocumentNo" />', '<xsl:value-of select="zero:Grade" />', 
<xsl:choose>
  <xsl:when test="zero:Traceable/@boolean = 'false'"><xsl:text>'N'</xsl:text></xsl:when>
  <xsl:otherwise><xsl:text>'Y'</xsl:text></xsl:otherwise>
  </xsl:choose>, 
  '<xsl:value-of select="zero:BiProduct" />', 
  <xsl:value-of select="format-number(zero:Surface/@number div 1000000, '#0.000')" />, 
  '<xsl:value-of select="zero:Calc" />', '<xsl:value-of select="zero:Discipline" />', 
  '<xsl:value-of select="zero:Designer" />', '<xsl:value-of select="zero:Name" />',
  <xsl:value-of select="../../../zero:PlantSeq/@number" />, '<xsl:value-of select="../../../zero:ObjectSeq/@number" />',
  '<xsl:value-of select="../../../zero:ObjectRev" />');
  </xsl:for-each-group>
  </xsl:for-each>

这是我要实现的目标：我希望汇总位置1上的数字，以便它只返回位置1的一个插入，而不返回两个。 Posno 2、3等相同。

INSERT INTO RAPP_ADM.MTO_POS_IMP_TAB (PROJECT_NO, MTO_OWNER_NO, POS_NO, PART_NO, DESCRIPTION, QTY, UNIT, TOT_LEN, TOT_WEIGHT, DRAWING, GRADE, TRACE, BI_PRODUCT, SURFACE, CALC, DISCIPLINE, MADE_BY, POS_NO2, PLT_SEQ, OBJECT_SQ, OBJECT_REVISION) VALUES 
('6111', '26-0008-R552-MOD-01-M', '1','PIP03D1160', 'PIPE sch.160 ASTM A790 UNS S31', 2.66, 'M', 2.66, 56.793, 'C097-RWP-L-XN-0057-01', 'sch.160 ASTM A790 UNS S31', 'N', '26-0008-R552-MOD-01-1', 0.559, 'N', 'L', 'sindre.thompson', '', 721, '1556750', '1');

我不知道自己在做什么错。我有明显的错误吗？

Answer 1

我猜不是

<xsl:for-each select="/zero:Zero/zero:MTOOwner/zero:DocumentNo/zero:BiProduct/zero:Part">
<xsl:for-each-group select="/" group-by="zero:POS_NO">
<xsl:sort select="zero:PosNo" />

您想要的

<xsl:for-each-group select="/zero:Zero/zero:MTOOwner/zero:DocumentNo/zero:BiProduct/zero:Part" group-by="zero:POS_NO">
  <xsl:sort select="current-grouping-key()" />

但这只是一个猜测，请向我们展示您的输入结构和所需的结果结构。

Answer 2

<xsl:for-each-group select="/">

可能是错误的，因为“ /”选择单个节点，并且对单个节点进行分组永远没有用。

但是在没有看到输入XML的情况下，很难告诉您应该写些什么。

XSL分组未给出任何结果

2 个答案: