我在弄清楚如何处理实数和虚数这个问题时遇到了麻烦。
这是我到目前为止的代码:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
class Complex {
public:
Complex();
Complex(double realNum);
Complex(double realNum, double imagNum);
//Complex(double real = 0.0, double imaginary = 0.0); This avoids the 3 above?
Complex(const Complex& obj);
private:
double real;
double imaginary;
};
int main () {
Complex *complexArray;
complexArray = new Complex[8];
ifstream myfile("complex.txt");
string line;
int i = 0;
if (myfile.is_open()) {
while (! myfile.eof()) {
getline(myfile, line);
complexArray[i] = line;
i++
};
myfile.close();
};
else {
cout << "Error. Could not find/open file." ;
}
return 0;
};
Complex::Complex(const Complex& obj) {
real = obj.real;
imaginary = obj.imaginary;
};
Complex::Complex () {
real = 0;
imaginary = 0;
};
Complex::Complex (double realNum) {
real = realNum;
imaginary = 0;
};
Complex::Complex (double realNum, double imagNum) {
real = realNum;
imaginary = imagNum;
};
所以我意识到我无法读复数并将其直接存储到我的数组中...
我在想也许我应该这样做?
执行循环以遍历字符串数组并进行循环...
无论如何,我只是困惑如何解决这个问题。
谢谢!
答案 0 :(得分:0)
我建议使用正则表达式。这是我的方法:
#include <iostream>
#include <fstream>
#include <string>
#include <regex>
int main() {
std::regex rgx("^(?=[iI.\\d+-])([+-]?(?:\\d+(?:\\.\\d*)?|\\.\\d+)(?:[eE][+-]?\\d+)?(?![iI.\\d]))?([+-]?(?:(?:\\d+(?:\\.\\d*)?|\\.\\d+)(?:[eE][+-]?\\d+)?)?)?[iI]$");
std::smatch match;
std::ifstream infile("complex.txt");
std::string line;
while (std::getline(infile, line)) {
if (std::regex_search(line, match, rgx)) {
std::cout << "text: " << match[0] << ", real: " << match[1] << ", imaginary: " << match[2] << std::endl;
}
}
}
正则表达式是对https://stackoverflow.com/a/50428157/1994239的编辑,适用于您提供的示例文本。
答案 1 :(得分:0)
您可以使用正则表达式来匹配仅包含虚数的行。以下是解决您问题的完整程序-
Process Explorer
答案 2 :(得分:0)
使用正则表达式进行验证。
#include <iostream>
#include <fstream>
#include <string>
#include <regex>
using namespace std;
class Complex
{
public:
Complex();
Complex(double realNum);
Complex(double realNum, double imagNum);
//Complex(double real = 0.0, double imaginary = 0.0); This avoids the 3 above?
Complex(const Complex& obj);
friend ostream & operator << (ostream &out, const Complex &c)
{
cout<<c.real<<" + "<<c.imaginary<<"i";
return out;
}
private:
double real;
double imaginary;
};
int main ()
{
Complex *complexArray;
complexArray = new Complex[8];
ifstream myfile("complex.txt");
string line;
int i = 0;
if (myfile.is_open())
{
while (! myfile.eof())
{
getline(myfile, line);
const std::string& str = line;
//use regex to identify if this line represents a complex number or not
double real = 0.0, imag = 0.0;
std::regex realRegex("^(-)?\\s*(\\d+(\\.\\d+)?)$");
std::regex imagRegex("^(-)?\\s*(\\d+(\\.\\d+)?)i$");
std::regex bothRegex("^(-)?\\s*(\\d+(\\.\\d+)?)\\s*([-+])\\s*(\\d+(\\.\\d+)?)i$");
std::smatch match;
if (std::regex_match(str.begin(), str.end(), match, realRegex))
{
real = std::atof(match[2].str().c_str());
if (match[1].matched)
{
real = -real;
}
}
else if (std::regex_match(str.begin(), str.end(), match, imagRegex))
{
imag = std::atof(match[2].str().c_str());
if (match[1].matched)
{
imag = -imag;
}
}
else if (std::regex_match(str.begin(), str.end(), match, bothRegex))
{
real = std::atof(match[2].str().c_str());
imag = std::atof(match[5].str().c_str());
if (match[1].matched)
{
real = -real;
}
if (match[4].str() == "-")
{
imag = -imag;
}
}
else
{
continue;
}
Complex c(real, imag);
cout<<c<<endl;
complexArray[i]=c;
i++;
}
myfile.close();
}
else
{
cout << "Error. Could not find/open file." ;
}
return 0;
};
Complex::Complex(const Complex& obj)
{
real = obj.real;
imaginary = obj.imaginary;
};
Complex::Complex ()
{
real = 0;
imaginary = 0;
};
Complex::Complex (double realNum)
{
real = realNum;
imaginary = 0;
};
Complex::Complex (double realNum, double imagNum)
{
real = realNum;
imaginary = imagNum;
};