Question

在此线性搜索代码中，执行了第8行后，它跳到了第13行，而没有执行for循环。

输出：输入数组的大小 5 输入元素输入要搜索的元素

代码如下：

import atob from 'atob';
import forge from 'node-forge';

const InitVector = [0x00, ...];
const EncryptionKey = 'Some Encryption Key';

const initKey = Buffer.from(InitVector).toString(); // Changed this to `initKey`

const convertBase64StringToUint8Array = input => {
  const data = atob(input);
  const array = Uint8Array.from(data, b => b.charCodeAt(0));

  return array;
};

const decrypt = cipher => {
  const cipherArray = convertBase64StringToUint8Array(cipher);

  const key = forge.pkcs5.pbkdf2(EncryptionKey, iv, 1000, 32);

  /**
   * Added the following
   * Note the key size = 48
   *  This was due to the fact that the C# dictated that
   *  the IV was 16 bytes, starting at the end of the key.
   */
  const keyAndIV = forge.pkcs5.pbkdf2(encryptionKey, initKey, 1000, 32 + 16);

  /**
   * Therefore, we cut the iv from the new string
   */
  const iv = keyAndIV.slice(32, 32 + 16); // 16 bytes

  const decipher = forge.cipher.createDecipher(
    'AES-CBC',
    forge.util.createBuffer(key)
  );

  decipher.start({ iv });

  decipher.update(forge.util.createBuffer(cipherArray, 'raw'));

  const result = decipher.finish();

  if (result) {
    return decipher.output.data;
  } else {
    return false;
  }
};

Answer 1

由于条件c > n，您没有进入for循环，请尝试将其更改为c < n。

for(c=0; c < n; c++)

为什么for循环未执行？（线性搜索）

1 个答案: