Question

在这里，我正在过滤与django User模型具有OnetoOne关系的人员。下面的功能def filter_staff_users(request):的代码也可以按我的要求很好地工作，但是我得到的问题是在消息中显示组织名称时。我尝试做organization.name，但没有成功。我得到了'str' object has no attribute 'name'，当我尝试转换int organization = int(request.GET.get('organization'))时，它再次抛出了'int' object has no attribute 'name'。

如何在此处显示组织名称？

models.py

class Organization(models.Model):
    name = models.CharField(max_length=255, unique=True)

    def __str__(self):
        return self.name

class Staff(models.Model):
    user = models.OneToOneField(get_user_model(), on_delete=models.CASCADE, related_name='staff')
    name = models.CharField(max_length=255, blank=True, null=True)
    organization = models.ForeignKey(Organization, on_delete=models.SET_NULL, blank=True, null=True, related_name='staff')

在添加staff_user时，我按如下所示添加了组织

<select  name="organization">

    {% for organization in organizations %}
        <option value="{{organization.pk}}" >{{organization.name}}</option>
    {% endfor %}

</select>

views.py

def filter_staff_users(request):
    year = request.GET.get('year')
    month = request.GET.get('month')
    # month_name = calendar.month_name[int(month)]
    organization = request.GET.get('organization')
    print('org', type(organization))

    if year and month and organization:
        staffs = get_user_model().objects.filter(Q(staff__joined_date__year=year) & Q(staff__joined_date__month=month) & Q(staff__organization=organization))

        messages.success(request, '{} staffs found for {}  {} and {}'.format(staffs.count(), year, calendar.month_name[int(month)], organization))

Answer 1

尝试做：

from django.shortcuts get_object_or_404

def filter_staff_users(request):
    # ...
    organization = get_object_or_404(Organization, pk=request.GET.get('organization'))
    print(organization.name)

这样做：

organization = request.GET.get('organization')

我们只得到pk (as a string)中的organization。您需要的是Organization模型的对象。

如何在Django中显示外键值而不是pk？

1 个答案: