Laravel如何将模型查询代码转换为DB :: query？

Question

代码1

public function index(Request $request)
{
   $posts = NewJob::orderBy('won', 'desc')->where('progress' , 'forwarded')->paginate(5);
   $clients = DB::select('select * from client_infos');

    if ($request->ajax()){
        return view('Admin.NewForwardedEntry.ajax', compact('posts', 'clients'));
    }
    else{
        return view('Admin.NewForwardedEntry.newjob', compact('posts', 'clients'));
    }
}

代码2

public function index(Request $request)
{

    $posts = DB::table('new_jobs')
    ->select('id', 'won', 'proj_name', 'department', 'district', 'time_estimate', 'proj_cost', 'proj_date', 'client_id', 'created_at', 'updated_at'**strong text**)
    ->orderBy('won', 'desc')
    ->where('progress', 'forwarded')
    ->paginate(5);

    $clients = DB::select('select * from client_infos');

    if ($request->ajax()){
        return view('Admin.NewForwardedEntry.ajax', compact('posts', 'clients'));
    }
    else{
        return view('Admin.NewForwardedEntry.newjob', compact('posts', 'clients'));
    }
}

代码1正常运行，但是我不明白为什么代码2无法正常工作？

我正在更改此代码，因为我必须使用两个表 New_jobs 和 client_infos 来获取数据，其中客户信息应该通过new_jobs来获取。