使用星期数和星期几格式的日期范围的总值？

Question

[每周汇总结果表

我想获取两个日期之间的汇总值。...这是我的代码

SELECT CASE
  WHEN DATEPART(dw,'2019-02-02') = 1THEN WD01
  WHEN DATEPART(dw,'2019-02-02') = 2 THEN WD02
  WHEN DATEPART(dw,'2019-02-02') = 3 THEN WD03
  WHEN DATEPART(dw,'2019-02-02') = 4 THEN WD04
  WHEN DATEPART(dw,'2019-02-02') = 5 THEN WD05
  WHEN DATEPART(dw,'2019-02-02') = 6 THEN WD06
  WHEN DATEPART(dw,'2019-02-02') = 7 THEN WD07
END AS VALUE,
CASE
  WHEN DATEPART(dw,'2019-02-28') = 1THEN WD01
  WHEN DATEPART(dw,'2019-02-28') = 2 THEN WD02
  WHEN DATEPART(dw,'2019-02-28') = 3 THEN WD03
  WHEN DATEPART(dw,'2019-02-28') = 4 THEN WD04
  WHEN DATEPART(dw,'2019-02-28') = 5 THEN WD05
  WHEN DATEPART(dw,'2019-02-28') = 6 THEN WD06
  WHEN DATEPART(dw,'2019-02-28') = 7 THEN WD07
END AS VALUE2
FROM SummaryWeeklyTest
WHERE cWeekNum BETWEEN DATEPART(wk,'2019-02-03') AND DATEPART(wk,'2019-02-28')

输出应为突出显示值的总和

Answer 1

如果您将数据发布为txt而不是图片，我会给出完整的答案。然而，作为其图像，这未经测试。应该可以给你这个主意。

我要做的是先扩展数据，然后轻松进行所需的操作：

;with days AS (
    select * from (values (1),(2),(3),(4),(5),(6),(7)) as t(d)
)
,expanded as (
    select terminal, cyear, cWeekNum, d, 
        case d 
            when 1 then WD01
            when 2 then WD02
            when 3 then WD03
            when 4 then WD04
            when 5 then WD05
            when 6 then WD06
            when 7 then WD07
        end as WD
    from SummaryWeeklytest
    cross join days
)
select sum(WD) from expanded 
where cWeekNum BETWEEN DATEPART(wk,'2019-02-03') AND DATEPART(wk,'2019-02-28')