我有一个viewPager2和FragmentStateAdapter,并且有Fragement1、2、3、4,我在fragment2中,想要删除fragment3,并在fragment2之后显示fragment4。 问题是它总是向我显示fragment3(data),调试显示fragment3已被删除,但是显示的页面仍然具有fragment3内容。
适应者:
class TipsAdapter(
private val items: MutableList<TripPage>,
context: FragmentActivity
) : FragmentStateAdapter(context) {
private val fragmentFactory = context.supportFragmentManager.fragmentFactory
private val classLoader = context.classLoader
override fun getItemCount(): Int = items.size
override fun createFragment(position: Int): Fragment {
val pageInfo = items[position]
val fragment = fragmentFactory.instantiate(classLoader, pageInfo.fragmentClass.name)
fragment.arguments = Bundle().also { it.putParcelable(PAGE_INFO, pageInfo) }
return fragment
}
fun getFragmentName(position: Int) = items[position].fragmentClass.simpleName
fun removeFragment(position: Int) {
items.removeAt(position)
notifyItemRemoved(position)
notifyItemRangeChanged(position, items.size)
notifyDataSetChanged()
}
}
删除片段代码:
if ((view_pager.adapter as TipsAdapter).getFragmentName(index + 1).equals(
TripPreFragment::class.simpleName) &&
viewModel.shouldRemoveBulkApply()) {
(view_pager.adapter as TipsAdapter).removeFragment(index + 1)
view_pager.setCurrentItem(index + 1, true)
} else {
view_pager.setCurrentItem(index + 1, true)
}
答案 0 :(得分:1)
最后,它对我有用。当我们调用MessageBox
时,android会调用
适配器中的方法notifyDataSetChanged()
,以检查项目是否已更新。它返回源代码中的位置。这意味着在列表getItemId()
中,如果删除0..i..n
,它将变成i
,0...i...n-1
不会更改,数据也不会自动更新。>
i
您需要做的是重写此方法和 /**
* Default implementation works for collections that don't add, move, remove items.
* <p>
* TODO(b/122670460): add lint rule
* When overriding, also override {@link #containsItem(long)}.
* <p>
* If the item is not a part of the collection, return {@link RecyclerView#NO_ID}.
*
* @param position Adapter position
* @return stable item id {@link RecyclerView.Adapter#hasStableIds()}
*/
@Override
public long getItemId(int position) {
return position;
}
,
对于我来说,我使用每个片段的哈希码:
containsItem(long)
}