我想等待排球响应返回，然后尝试使用RequestFuture get方法解决此问题，但 “ future.get（REQUEST_TIMEOUT，TimeUnit.SECONDS）”行生成系统错误。如何解决此问题 这是我的代码
public class ApiController {
private final String server="http://192.168.1.23/";
private static ApiController api=null;
private ApiController() {
}
public static ApiController getApiController(){
if(api==null){
api=new ApiController();
}
return api;
}
public JSONObject checkConlogin(String uname, String pass, Context context){
return getJSONObject(getresponse(server+"Conductor_login.php?uname="+uname+"&pass="+pass,context));
}
private String getresponse(String urlString,Context context){
String line=null;
RequestQueue queue = Volley.newRequestQueue(context);
RequestFuture<String> future = RequestFuture.newFuture();
StringRequest stringRequest = new StringRequest(Request.Method.GET, urlString, future, future);
queue.add(stringRequest);
int REQUEST_TIMEOUT = 10;
try {
line= future.get(REQUEST_TIMEOUT, TimeUnit.SECONDS);
} catch (InterruptedException|ExecutionException |TimeoutException e) {
}
return line;
}
private JSONObject getJSONObject(String line) {
try {
return new JSONObject(line);
} catch (JSONException e) {
e.printStackTrace();
return null;
}
}
}
导体类调用ApiController checkConlogin方法，并获取上下文，用户名和密码以获取json对象
public class Conductor {
public static int conid;
public boolean login(Context context, String username, String password) {
JSONObject jsonObject = ApiController.getApiController().checkConlogin(username,password,context); try {
if("done".equalsIgnoreCase(jsonObject.getString("status"))){
conid=Integer.valueOf(jsonObject.getString("id"));
return true;
}else{
Toast.makeText(context,jsonObject.getString("message"), Toast.LENGTH_SHORT).show();
}
return false;
} catch (JSONException e) {
e.printStackTrace();
return false;
}
}
}
MainActivity类调用Conductor类以使用活动上下文，用户名和密码登录响应
public class MainActivity extends AppCompatActivity {
private EditText uname,pass;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
uname=findViewById(R.id.uname);
pass=findViewById(R.id.pass);
}
public void login(View v){
Conductor c=new Conductor();
if(c.login(this,uname.getText().toString(),pass.getText().toString())){
Intent mainmenu=new Intent(MainActivity.this, MainManu.class);
startActivity(mainmenu);
finish();
}
}
}
