因此,我尝试通过以某种形式拖动鼠标来绘制矩形,但是我成功了,但是当我尝试在图片框中进行相同的操作时,没有创建矩形。
Private Sub PictureBox1_MouseMove(sender As Object, e As MouseEventArgs) Handles PictureBox1.MouseMove
If fGMouseIsDown And Not PictureBox1.Image Is Nothing Then
rect.Width = e.X - rect.X
rect.Height = e.Y - rect.Y
Invalidate()
End If
End Sub
Private Sub PictureBox1_MouseDown(sender As Object, e As MouseEventArgs) Handles PictureBox1.MouseDown
fGMouseIsDown = True
rect.Location = e.Location
rect.Width = 0
rect.Height = 0
Invalidate()
End Sub
Private Sub PictureBox1_Paint(sender As Object, e As PaintEventArgs) Handles PictureBox1.Paint
e.Graphics.DrawRectangle(Pens.Blue, rect)
End Sub
答案 0 :(得分:2)
每个@HansPassant:Invalidate()
方法中的PictureBox1_MouseDown()
调用使表单无效,而您想使图片框无效。
该通话应改为:
PictureBox1.Invalidate()
此外,请确保以正确的方式拖动;仅当您从左上角转到右下角时,此功能才有效。