Question

我有两个模型User和AccountType

class User extends Authenticatable
{
    (...)

    public function accountType()
    {
        return $this->belongsTo('App\AccountType', 'account_type_id', 'id');
    }
}

class AccountType extends Model
{
  protected $table = 'account_types';
  // protected $primaryKey = 'id';

  public function users()
  {
      return $this->hasMany('App\User');
  }
}

我的数据库：

        Schema::create('users', function (Blueprint $table) {
            $table->bigIncrements('id');
            $table->bigInteger('account_type_id')->unsigned();
            $table->foreign('account_type_id')->references('id')->on('account_types');
            $table->string('full_name');
            $table->string('email')->unique();
            $table->timestamp('email_verified_at')->nullable();
            $table->string('password');
            $table->rememberToken();
            $table->timestamps();
        });

        Schema::create('account_types', function (Blueprint $table) {
            $table->bigIncrements('id');
            $table->string('account_type_name');
        });

当我使用hasMany时-一切都像一个超级按钮，但是当我尝试使用$user->accountType->account_type_name时却不起作用。我用来打印用户的循环：

                @foreach ($users as $user)
                  <tr>
                    <td>{{ $user->full_name }}</td>
                    <td>
                      <a href="#" class="badge badge-pill badge-warning">No team</a>
                    </td>
                    <td>
                      xyz
                    </td>
                    <td> {{ $user->accountType->account_type_name }} </td>
                    <td><a href="mailto:{{ $user->email }}">{{ $user->email }}</a></td>
                    <td>{{ $user->created_at }}</td>
                  </tr>
                @endforeach

和错误。当我将$user->accountType->account_type_name注释掉时，效果很好。

ErrorException
Undefined offset: 1

详细信息-https://flareapp.io/share/jKPgOZPa

提前谢谢！

Answer 1

您需要使用蛇案而不是骆驼案：

<td> {{ $user->account_type->account_type_name }} </td>

Answer 2

好像您定义了错误的关系。您的用户模型应类似于：

class User extends Authenticatable
{
    (...)

    public function accountType()
    {
        return $this->hasOne('App\AccountType', 'account_type_id', 'id');
    }
}

和帐户类型模型应类似于：

class AccountType extends Model
{
     protected $table = 'account_types';
    // protected $primaryKey = 'id';

    public function user()
    {
       return $this->belongsTo('App\User');
    }
}

Answer 3

我已将<td> {{ App\User::find($user->id)->accountType->account_type_name }} </td>替换为{{1}}，现在一切正常。

Answer 4

您可以尝试一下。...我的工作正常。

$user->accountType->first() ->account_type_name

为什么BelongsTo（）在Laravel 6中不起作用？

4 个答案: