Question

我有一个很难解释的问题。我有两个桌子

表1 ：（这类似于装运表）

ID  ShippingId ProductId1 ProductId2 
1   100        A          A1
2   100        A          A2
3   100        A          A3
4   100        A          A4
5   100        A          A5

6   200        B          B1
7   200        B          B2

8   300        B          A1
9   300        B          A2

表2 ：（这与ProductId1和ProductId2之间的关系有关）

ID  ProductId1 ProductId2 
1   A          A1
2   A          A2
3   A          A3
4   A          A4
5   A          A5
6   B          B1
7   B          B2

如果装运“ 100”包括所有“ A”项目，则应为“ true” 发货“ 200”和“ 300”不包括其主要产品的所有部分。所以预期的输出应该像

ShippingId ProductId1 IsIncludeAll
100        A          true
200        B          false
300        A          true

你们能帮我吗？

DECLARE @table1 AS TABLE
(
    ShippingID INT,
    ProductId1 INT,
    ProductId2 INT
)
DECLARE @table2 AS TABLE
(
    ProductId1 INT,
    ProductId2 INT
)

INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (100,111, 1119)
INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (100,111, 1118)
INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (100,111, 1117)
INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (100,111, 1116)
INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (100,111, 1115)

INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (200,222, 2229)
INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (200,222, 2228)
INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (300,111, 1117)
INSERT INTO @table1 (ShippingId,ProductId1,ProductId2) VALUES (300,111, 1116)


INSERT INTO @table2 (ProductId1,ProductId2) VALUES ( 111, 1119)
INSERT INTO @table2 (ProductId1,ProductId2) VALUES ( 111, 1118)
INSERT INTO @table2 (ProductId1,ProductId2) VALUES ( 111, 1117)
INSERT INTO @table2 (ProductId1,ProductId2) VALUES ( 111, 1116)
INSERT INTO @table2 (ProductId1,ProductId2) VALUES ( 111, 1115)

INSERT INTO @table2 (ProductId1,ProductId2) VALUES ( 222, 2229)
INSERT INTO @table2 (ProductId1,ProductId2) VALUES ( 222, 2228)



ShippingId ProductId1 IsIncludeAll
100        A          true
200        B          false
300        A          false

Answer 1

总的猜测是，样本DDL和DML与样本数据不匹配，但这也许是这样吗？

SELECT S.ShippingID,
       T2.ProductId1,
       CASE COUNT(CASE WHEN T1.ProductId2 IS NULL THEN 1 END) WHEN 0 THEN 'true' ELSE 'false' END AS IsIncludeAll
FROM @table2 T2
     CROSS APPLY (SELECT DISTINCT
                         sq.ShippingID,
                         sq.ProductId1
                 FROM @table1 sq
                 WHERE sq.ProductId1 = T2.ProductId1) S
     LEFT JOIN @table1 T1 ON T2.ProductId1 = T2.ProductId1
                         AND T1.ProductId2 = T2.ProductId2
                         AND S.ShippingID = T1.ShippingID
GROUP BY S.ShippingID,
         T2.ProductId1;

Answer 2

对样本数据和输出有点困惑。根据我的想法，请检查此查询并输出。

------Step 1. concatenate product1 and product2 with ShippingID wise,product1 wise order by ShippingID,ProductId1,ProductId2-------------------
declare @Shipping as table
(
    ShippingID INT,
    ProductId1 INT,
    ProductDesc varchar(max)
)
insert @Shipping
SELECT Shipping.ShippingID,Shipping.ProductId1,
       LEFT(Shipping.prod_desc,Len(Shipping.prod_desc)-1) As prod_desc 
FROM
    (
        SELECT DISTINCT T2.ShippingID, T2.ProductId1,
            (
                SELECT cast(T1.ProductId1 as varchar(10))+'-' +cast(T1.ProductId2 as varchar(10))+ '|' AS [text()]
                FROM dbo.table1 T1
                WHERE T1.ShippingID = T2.ShippingID and T1.ProductId1=T2.ProductId1 
                ORDER BY T1.ShippingID,ProductId1,ProductId2
                FOR XML PATH ('')
            ) prod_desc
        FROM dbo.table1 T2
    ) Shipping

------Step 2. concatenate product1 and product2 with product1 wise order by ProductId1,ProductId2-------------------    
declare @relation as table
(
    ProductId1 INT,
    ProductDesc varchar(max)
) 
insert @relation
SELECT   relation.ProductId1,LEFT(relation.prod_desc,Len(relation.prod_desc)-1) As prod_desc 
FROM
    (
        SELECT DISTINCT T2.ProductId1, 
            (
                SELECT cast(T1.ProductId1 as varchar(10))+'-' +cast(T1.ProductId2 as varchar(10))+ '|' AS [text()]
                FROM dbo.table2 T1
                WHERE T1.ProductId1=T2.ProductId1 
                ORDER BY ProductId1,ProductId2
                FOR XML PATH ('')
            ) prod_desc
        FROM dbo.table2 T2
    ) relation


------Step 1. use left join to match with concatinated string of every product1. if matches return True otherwise False-------------------    
select a.ShippingID,a.ProductId1,case when b.ProductDesc is null then 'False' else 'True' end as IsIncludeAll 
from @Shipping a
left join @relation b
on a.ProductId1=b.ProductId1 and a.ProductDesc=b.ProductDesc


-----Result-----------

------------+---------------+--------------
ShippingID  | ProductId1    | IsIncludeAll
------------+---------------+--------------
100         | 111           | True
200         | 222           | True
300         | 111           | False

获取两个表之间的完全匹配

2 个答案: