这里出了什么问题-MySQLi和Custom类

时间:2011-04-26 13:25:31

标签: php mysql database mysqli

我正在创建一个继承自DBManager类的自定义用户管理类。到目前为止我遇到的问题是使用mysqli预处理语句执行查询。 DB连接正常但是然后prepare语句失败。我有mysqli对象作为在类中共享的属性。我是这个mysqli的新手(我一直使用普通的mysql)。下面是失败的构造函数和insertusers方法。 谢谢你的帮助,我已经搜索了这么久了,所以请原谅我,如果在某个地方有这样的东西。我找不到它。 再次感谢

<?php

protected  $dbLink;
protected  $errorMsg = array();//Inherited by other functions

public function __construct() {
$this->dbLink = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);
if (mysqli_connect_errno()) {
    $this->addError(mysqli_connect_error());
}
}

public  function insertUsers($arrayofValues) {
        //for inserting users in the database
        $sql = "INSERT INTO users(firstname, lastname, email, username, password) VALUES(?, ?, ?, ?, ?";
        if( $stmt = $this->dbLink->prepare($sql)) {
            $type = array("sssss");
            $params = array_merge($type, $arrayofValues);
            call_user_func_array(array($stmt, 'bind_param'), $this->refValues($params));
            $stmt->execute();

            if($stmt==-1) {
                //query failed
                $this->addError(mysqli_connect_error());
                return false;
            }else {
                return true;
            }
        }
        else{
            $this->addError("Something went wrong before InsertUsers stmt could execute well");
        }
    }
?>

1 个答案:

答案 0 :(得分:2)

关闭INSERT中的parens:

INSERT INTO users(firstname, lastname, email, username, password) VALUES(?, ?, ?, ?, ?)
                                                                                      ^

它通常有助于在代码中添加确切的错误描述:

        $this->addError("InsertUsers failed: " . $this->dblink->error);