我正在构建一个数据库,该数据库将我的本地产品目录与外国产品目录匹配。当我只有唯一的表'Catalog'
时,SQLAlchemy可以正常工作。在添加表Competitors
和Competitors_catalog
之后,我所有尝试将记录添加到两个新表中的尝试均返回了错误。
AttributeError:“表”对象没有属性“ id”
我多次更改/删除/播放Competitors
和Competitors_catalog
之间的关系,并通过flask-migrate
来回删除和创建表,但始终收到相同的错误。
像Competitors.query.all()
这样的简单查询将返回相同的结果。
删除了db.relationship()
-同样的结果。
然后,我最终回滚到一个清晰的数据库,并从头开始使用flask-migrate
对其进行了初始化。之后,我开始尝试将记录添加到Catalog
表中时收到相同的错误,在回滚之前,它工作正常。奇怪的是,我没有对代码的那部分进行任何更改。
class Catalog(db.Model):
__tablename__ = 'catalog'
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(60), index=True, nullable=False)
parent_id = db.Column(db.Integer, db.ForeignKey('catalog.id'), default=None)
url = db.Column(db.String())
created = db.Column(db.DateTime, default=datetime.now())
last_modified = db.Column(db.DateTime, index=True, onupdate=datetime.now())
categories = db.relationship('Catalog', remote_side='catalog.id', backref='parent')
class Competitors(db.Model):
__tablename__ = 'competitors'
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(40), index=True, nullable=False)
base_url = db.Column(db.String())
cat_url = db.Column(db.String())
created = db.Column(db.DateTime, default=datetime.now())
last_modified = db.Column(db.DateTime, onupdate=datetime.now(), default=datetime.now())
sells = db.relationship('Competitors_catalog', backref='competitor', cascade="all, delete-orphan", passive_deletes=True, lazy='dynamic')
class CompCatalog(db.Model):
__tablename__ = 'compcatalog'
id = db.Column(db.Integer, primary_key=True)
out_id = db.Column(db.Integer)
name = db.Column(db.String(60), index=True, nullable=False)
top_section = db.Column(db.Integer, default=None)
comp_id = db.Column(db.Integer, db.ForeignKey('competitors.id', ondelete="CASCADE"))
url = db.Column(db.String())
created = db.Column(db.DateTime, default=datetime.now())
last_modified = db.Column(db.DateTime, index=True, onupdate=datetime.now())
简单创建新实例将返回错误。但是在回滚之前效果很好。
from .models import Catalog
name = 'Apple'
rec = Catalog(name=name)
Traceback (most recent call last):
File "<console>", line 1, in <module>
File ".../app/helpers.py", line 31, in create_catalog
rec = Catalog(name=name)
File "<string>", line 2, in __init__
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/orm/instrumentation.py", line 376, in _new_state_if_none
state = self._state_constructor(instance, self)
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/util/langhelpers.py", line 855, in __get__
obj.__dict__[self.__name__] = result = self.fget(obj)
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/orm/instrumentation.py", line 202, in _state_constructor
self.dispatch.first_init(self, self.class_)
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/event/attr.py", line 322, in __call__
fn(*args, **kw)
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/orm/mapper.py", line 3360, in _event_on_first_init
configure_mappers()
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/orm/mapper.py", line 3248, in configure_mappers
mapper._post_configure_properties()
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/orm/mapper.py", line 1947, in _post_configure_properties
prop.init()
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/orm/interfaces.py", line 196, in init
self.do_init()
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/orm/relationships.py", line 1860, in do_init
self._process_dependent_arguments()
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/orm/relationships.py", line 1889, in _process_dependent_arguments
setattr(self, attr, attr_value())
File ".../.virtualenvs/.../lib/python3.6/site-packages/sqlalchemy/ext/declarative/clsregistry.py", line 294, in __call__
x = eval(self.arg, globals(), self._dict)
File "<string>", line 1, in <module>
AttributeError: 'Table' object has no attribute 'id'
答案 0 :(得分:0)
您可以将remote_side
参数作为可评估的字符串进行传递:
remote_side='catalog.id'
问题在于,在其中评估的名称空间包含Table
对象和模型类,并且您引用的是Table
而不是模型类。只需将远端更改为
remote_side='Catalog.id'
或直接在类主体中传递id
列:
class Catalog(db.Model):
__tablename__ = 'catalog'
id = db.Column(db.Integer, primary_key=True)
...
categories = db.relationship('Catalog', remote_side=id, backref='parent')