所以我在c ++中有以下内容
__declspec(dllexport) extern "C"
char** get_prop_types( int* count ) {
const vector<string>& r = prop_manager::get_prop_types();
char **p = (char**)malloc( r.size() );
char **ptr = p;
for( vector<string>::const_iterator it = r.begin(); it!=r.end() ; ++it ) {
*p = (char*)malloc( it->size() );
strcpy(*p++,it->c_str());
}
*count = r.size();
return ptr;
}
和java
public interface Arch extends Library {
public Pointer get_prop_types( IntByReference size );
}
static Arch theLib; //initialization not shown
public static String[] getPropTypes() {
IntByReference size = new IntByReference();
Pointer strs = theLib.get_prop_types(size);
//free is apparently handled for us?
return strs.getStringArray(0, size.getValue());
}
public static void main( String[] args ) {
System.out.println( Arrays.toString(getPropTypes()) );
}
以上将打印出一个字符串列表。到现在为止还挺好。但是在主要回归之后(在最终确定期间?),我得到了一个错误
The instruction at "%08X" referenced memory at "%08x". The memory could not be "read".
尝试手动free()
char**
或每个人char*
有人可以告诉我我做错了什么吗?或者至少指出我们还有更多的资源?
答案 0 :(得分:1)
此:
*p = (char*)malloc( it->size() );
应该是:
*p = (char*)malloc( it->size() + 1);
我刚注意到:
char **p = (char**)malloc( r.size() );
应该是:
char **p = (char**)malloc( r.size() * sizeof(char *) );
显示我最近经常使用malloc!