Question

我正在处理必须执行导入导出功能的Web应用程序。我是新手，所以我想向您提出建议，并且在执行此功能时遇到一些问题，

所以首先我有一个来自Frontend（AngularJs）的JSON数组

[
    {
      "MyName": "Shubham",
      "UserType": "Premium",
      "DialCode": "India",
      "ContactNumber": "9876543210",
      "EmailAddress": "Contact@Shubh.com"
      "Country": "India",
      "Notes": "Notes-Notes-Notes-Notes"
    },
    {
      "MyName": "Shubham 2",
      "UserType": "Free Trial",
      "DialCode": "India",
      "ContactNumber": "123456789",
      "EmailAddress": "Contact2@Shubh.com"
      "Country": "India",
      "Notes": "Notes-Notes-Notes-Notes"
    }   ]

现在我正在使用XMLbuilder将此数组转换为NodeJ中的XML 像这样

<UserXML>
    <MyName>Shubham</MyName>
    <UserType>Premium</UserType>
    <DialCode>India</DialCode>
    <ContactNumber>9876543210</ContactNumber>
    <EmailAddress>Contact@Shubh.com</EmailAddress>
    <Country>India</Country>
    <Notes>Notes-Notes-Notes-Notes</Notes>
</UserXML>
<UserXML>
    <MyName>Shubham 2</MyName>
    <UserType>Free Trial</UserType>
    <DialCode>India</DialCode>
    <ContactNumber>123456789</ContactNumber>
    <EmailAddress>Contact2@Shubh.com</EmailAddress>
    <Country>India</Country>
    <Notes>Notes2-Notes2-Notes2-Notes2</Notes>
</UserXML>

现在我正在SQL Server中使用此XML将这2条记录插入到我的用户表中现在的问题是我还有另一个保存国家代码和国家名称的表，我在用户表中使用外键引用我已经制作了示例代码

DROP TABLE IF EXISTS #Country
DROP TABLE IF EXISTS #user
DROP TABLE IF EXISTS #UserType


 CREATE TABLE #Country
(
    Id INT PRIMARY KEY  identity(1 ,1),
    Name VARCHAR(50) NOT NULL,
    DialCode VARCHAR(50) NOT NULL
 )
 CREATE TABLE #UserType
(
    Id INT PRIMARY KEY  identity(1 ,1),
    Name VARCHAR(50) NOT NULL
 )
 CREATE TABLE #user
(
    Id                INT PRIMARY KEY  IDENTITY(1 ,1),
    Name              VARCHAR(50) NOT NULL,
    UserTypeId        INT NOT NULL,
    DialCodeId        INT NOT NULL,
    ContactNumber     VARCHAR(50) NOT NULL,
    EmailAddress      VARCHAR(50) NOT NULL,
    CountryId         INT NOT NULL,
    Notes      VARCHAR(50) NOT NULL
   FOREIGN KEY(CountryId) REFERENCES #Country(Id),
   FOREIGN KEY(UserTypeId) REFERENCES #UserType(Id)
);



INSERT INTO #Country (Name,DialCode)
VALUES ('India','+91'), 
       ('Dubai','+971'),
       ('U.S','+1') ;
INSERT INTO #UserType (Name)
VALUES ('Premium'), 
       ('Free Trial');

案例1（工作正常），如果我只有一条记录，那么使用此方法不会有问题

declare @xml xml = '<UserXML>
    <Name>Shubham CASE-1</Name>
    <UserType>Premium</UserType>
    <DialCode>India</DialCode>
    <ContactNumber>9876543210</ContactNumber>
    <EmailAddress>Contact@Shubh.com</EmailAddress>
    <Country>India</Country>
    <Notes>Notes-Notes-Notes-Notes CASE-1</Notes>
</UserXML>'

现在我必须检查国家/地区名称/用户类型，并将其与国家/地区表匹配以获取ID

DECLARE @CountryId INT 
       ,@UserType INT
SELECT @CountryId = id FROM #Country WHERE Name LIKE ''+(select U.Items.value('./DialCode[1]','NVARCHAR(200)') as DialCode FROM @xml.nodes('/UserXML') U(Items))+'%'
SELECT @UserType = id FROM #UserType WHERE Name LIKE ''+(select U.Items.value('./UserType[1]','NVARCHAR(200)') as UserType FROM @xml.nodes('/UserXML') U(Items))+'%'


INSERT INTO #user 
                SELECT 
                U.Item.query('./Name').value('.','VARCHAR(100)') Name,
                @UserType,
                @CountryId,
                U.Item.query('./ContactNumber').value('.','VARCHAR(100)') ContactNumber,
                U.Item.query('./EmailAddress').value('.','VARCHAR(100)') EmailAddress,
                @CountryId,
                U.Item.query('./Notes').value('.','VARCHAR(100)') Notes
                FROM @Xml.nodes('/UserXML') AS U(Item)

案例2（问题在这里），如果我有多个记录，那我该如何检查每个节点，然后进行联接或类似的操作，以使我的插入查询正常工作

declare @xml2 xml = '<UserXML>
    <Name>Shubham CASE-2</Name>
    <UserType>Premium</UserType>
    <DialCode>India</DialCode>
    <ContactNumber>9876543210</ContactNumber>
    <EmailAddress>Contact@Shubh.com</EmailAddress>
    <Country>India</Country>
    <Notes>Notes-Notes-Notes-Notes CASE-2</Notes>
</UserXML>
<UserXML>
    <Name>Shubham 2 CASE-2</Name>
    <UserType>Free Trial</UserType>
    <DialCode>Dubai</DialCode>
    <ContactNumber>123456789</ContactNumber>
    <EmailAddress>Contact2@Shubh.com</EmailAddress>
    <Country>Dubai</Country>
    <Notes>Notes2-Notes2-Notes2-Notes2 CASE-2</Notes>
</UserXML>'

DECLARE @CountryId2 INT 
       ,@UserType2 INT
SELECT @CountryId2 = id FROM #Country WHERE Name LIKE ''+(select U.Items.value('./DialCode[1]','NVARCHAR(200)') as DialCode FROM @xml2.nodes('/UserXML') U(Items))+'%'
SELECT @UserType2 = id FROM #UserType WHERE Name LIKE ''+(select U.Items.value('./UserType[1]','NVARCHAR(200)') as UserType FROM @xml2.nodes('/UserXML') U(Items))+'%'


INSERT INTO #user 
                SELECT 
                U.Item.query('./Name').value('.','VARCHAR(100)') Name,
                @UserType,
                @CountryId,
                U.Item.query('./ContactNumber').value('.','VARCHAR(100)') ContactNumber,
--              U.Item.query('./EmailAddress').value('.','VARCHAR(100)') EmailAddress,
                @CountryId,
                U.Item.query('./Notes').value('.','VARCHAR(100)') Notes
                FROM @xml2.nodes('/UserXML') AS U(Item)

如果您对执行此任务有任何建议或其他更好的方法，请帮帮我，我是新来的，所以我不知道执行此任务的最佳方法

Answer 1

您可以直接读取JSON并执行JOIN

SELECT entity.*
 FROM OPENROWSET (BULK N'd:\temp\file.json', SINGLE_CLOB) as j
 CROSS APPLY OPENJSON(BulkColumn)
 WITH(
    MyName nvarchar(100)
   ,UserType nvarchar(100)
   ,DialCode nvarchar(100)
   ,ContactNumber nvarchar(100)
   ,EmailAddress nvarchar(100)
   ,Country nvarchar(100)
   ,Notes nvarchar(500)
 ) AS entity

有关import JSON documents和OPENJSON的更多信息

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