Question

device_token包含方括号和空格，我想在有效载荷中删除它

这是去往供应商API的JSON负载

{
    "audience": {
        "device_token": "< XXXX XXXX XXXX XXXX >"
    },
    "device_types": [
            "ios"
    ],
    "notification": {
        "ios": {
            "alert": {
                "title": "INSERT_TITLE_TEXT_HERE",
                "body": "INSERT_BODY_TEXT_HERE"
            }
        }
     }
}

我希望JSON具有device_token：

{
    "audience": {
        "device_token": "XXXXXXXXXXXXXXXX"
    },
    "device_types": [
            "ios"
    ],
    "notification": {
        "ios": {
            "alert": {
                "title": "INSERT_TITLE_TEXT_HERE",
                "body": "INSERT_BODY_TEXT_HERE"
            }
        }
     }
}

Answer 1

假设处理语言为javascript：

json.audience.device_token = json.audience.device_token.replace(/[<> ]/g, '')

有关更多信息，请阅读String.prototype.replace文档：https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace

Answer 2

首先，您将JSON对象更改为字符串，然后替换您想要的文本。

类似的东西：

// Define the payload object
var jsonPayload = {
    "audience": {
        "device_token": "< XXXX XXXX XXXX XXXX >"
    },
    "device_types": [
            "ios"
    ],
    "notification": {
        "ios": {
            "alert": {
                "title": "INSERT_TITLE_TEXT_HERE",
                "body": "INSERT_BODY_TEXT_HERE"
            }
        }
     }
};
// Turn the object into a String
var string = JSON.stringify(jsonPayload);
// Replace the arrows and spaces with empty strings
var updatedString = string.replace(/< /g,'').replace(/ >/g,'').replace(/\s/g,'');
// Replace the jsonPayload with your new version by parsing the string 
// where replacements have been made back into a JSON object;
jsonPayload = JSON.parse(updatedString);

应该可以！

带走json字符串中的括号和空格

2 个答案: