如何通过在.net中给出子值来读取父xml

Question

<?xml version="1.0" encoding="utf-8" ?>
<PrimaryLink>
  <LinkID>p1</LinkID>
    <SecondaryLink>
      <LinkID>s1</LinkID>      
        <LeftMenu>
          <NavLinks>
            <LinkID>n1</LinkID>
          </NavLinks>
          <NavLinks>
            <LinkID>n2 </LinkID>               
          </NavLinks>
        </LeftMenu>
    </SecondaryLink>  
</PrimaryLink>

C＃

var menuItems1 = from c in xMenuElement.Elements("GlobalNavigation").Elements("PrimaryLink")
                 select c;

通过将n1作为输入

，我喜欢p1->s1->n1的ans

Answer 1

这是一个解决方案。它不是很漂亮，但它可以满足您的需求。

 string xmlContent=@"<?xml version=""1.0"" encoding=""utf-8"" ?>
                                <PrimaryLink>
                                  <LinkID>p1</LinkID>
                                    <SecondaryLink>
                                      <LinkID>s1</LinkID>      
                                        <LeftMenu>
                                          <NavLinks>
                                            <LinkID>n1</LinkID>
                                          </NavLinks>
                                          <NavLinks>
                                            <LinkID>n2</LinkID>               
                                          </NavLinks>
                                        </LeftMenu>
                                    </SecondaryLink>  
                                </PrimaryLink>";

        XDocument doc = XDocument.Parse(xmlContent);
        var targetNode = doc.Descendants().Where(p=>p.Value=="n1").FirstOrDefault();
        string path = null;
        if (targetNode!=null)
        {
            path=targetNode.AncestorsAndSelf().Elements("LinkID").Select(p => p.Value).Aggregate((i, j) => j + "=>" + i);
        }

它将显示“p1 =＆gt; s1 =＆gt; n1”