Question

我在给我1个参数但给出2个参数时出错，最终目标是打印json正文

url_get = 'http://ludwig.corp.podiumdata.com:/qdc/entity/v1/getEntities?type=EXTERNAL&count=2&sortAttr=name&sortDir=ASC'
session = requests.Session()
r = session.get(url_cookie, auth=(username,password), verify=False)
print('--------------------- 1. status_code ----------------------------------')
print(r.status_code)
print('--------------------- 1. headers ----------------------------------')
print(r.headers)
print('--------------------- 1. content ----------------------------------')
data = r.json(url_get)
print(data)
print('--------------------- 1. cookies ----------------------------------')
print(session.cookies, r.cookies)
print('--------------------- 1. cookies get_dict ----------------------------------')
print(session.cookies.get_dict())
print("7")

  File "<ipython-input-36-b971c3b17ea5>", line 67, in <module>
    data = r.json(url_get)

TypeError: json() takes 1 positional argument but 2 were given```

Answer 1

这是因为您尝试在URL上调用tableView.reloadData，该URL不适合python中的任何有效对象。

json.loads

我确定错误消息看起来很熟悉：）

接下来，当您在import json x = json.loads('[1, 2, 3]') x # This gets evaluated to a list [1, 2, 3] y = json.loads('hi i am a string') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/Users/mm92400/anaconda3/lib/python3.6/json/__init__.py", line 354, in loads return _default_decoder.decode(s) File "/Users/mm92400/anaconda3/lib/python3.6/json/decoder.py", line 339, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File "/Users/mm92400/anaconda3/lib/python3.6/json/decoder.py", line 357, in raw_decode raise JSONDecodeError("Expecting value", s, err.value) from None json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)对象上调用json方法时，您无需传递任何内容，因为请求的主体将隐式传递给{{1} }解析器：

Request

json的文档为here，r = requests.get(some_url) r.json() # don't put anything in the parens here的文档为here

Answer 2

您的意思是说r.json()。 r是代表从服务器返回的数据的响应对象。对此调用json()方法（尝试）将JSON中的数据解析为python数据结构。您不能将任何其他参数传递给该函数。

Json接受了1个位置参数，但给出了2个

2 个答案: