Question

我正在尝试替换某一行的特定位置的单词

例如，给定：

INSERT INTO address (city_id,city) VALUES (1,'Monrovia');
INSERT INTO address (city_id,city) VALUES (2,'Brunswick');
INSERT INTO address (city_id,city) VALUES (3,'Phenix City');

我想用“底特律”替换所有不同的城市，结果是：

INSERT INTO address (city_id,city) VALUES (1,'Detroit');
INSERT INTO address (city_id,city) VALUES (2,'Detroit');
INSERT INTO address (city_id,city) VALUES (3,'Detroit');

请问，我怎样才能在sed，awk或vim中这样做？

谢谢。

Answer 1

咦？这很简单：

$ echo "INSERT INTO address (city_id,city) VALUES (1,'Monrovia');
> INSERT INTO address (city_id,city) VALUES (2,'Brunswick'); 
> INSERT INTO address (city_id,city) VALUES (3,'Phenix City');" | 
> sed "s/'[^']*'/'Detroit'/g"
INSERT INTO address (city_id,city) VALUES (1,'Detroit'); 
INSERT INTO address (city_id,city) VALUES (2,'Detroit'); 
INSERT INTO address (city_id,city) VALUES (3,'Detroit');

干杯。基思。

Answer 2

最简单：保留脚本，追加

UPDATE address SET city ='Detroit'

在vim中：

:g/^INSERT INTO address/normal f;F'ci'Detroit

在sed：

sed "s/\(VALUES (.*,\)'.*\?'/\1'Detroit'/g"

sed / awk替换句子特定位置的单词

2 个答案: