（颤振）弯曲到CustomPaint小部件的边缘

Question

这就是我要构建的：

（仅查看appBar的形状，而不查看内容）

David

这就是我所拥有的：

我希望边缘弯曲而不是太尖锐。

这是我的CustomPaint代码：

class LogoPainter extends CustomPainter {
  @override
  void paint(Canvas canvas, Size size) {
    Paint paint = Paint();
    paint.color = Colors.blue;
    var path = Path();
    path.lineTo(0, size.height - size.height / 5);
    path.lineTo(size.width / 1.2, size.height);
    path.lineTo(size.width, size.height - size.height / 5);
    path.lineTo(size.width, 0);
    path.close();
    canvas.drawPath(path, paint);
  }

  @override
  bool shouldRepaint(CustomPainter oldDelegate) {
    return true;
  }
}

如何获得此弯曲边缘？

我尝试过point.arcToPoint()和point.quadraticBezierTo()，但没有成功。

Answer 1

这不是完美的，但是您可以摆弄一些数字：

class LogoPainter extends CustomPainter {
  @override
  void paint(Canvas canvas, Size size) {
    Paint paint = Paint();
    paint.color = Colors.blue;
    var path = Path();
    path.lineTo(0, size.height - size.height / 5);
    path.lineTo(size.width / 1.2, size.height);
    //Added this line
    path.relativeQuadraticBezierTo(15, 3, 30, -5);
    path.lineTo(size.width, size.height - size.height / 5);
    path.lineTo(size.width, 0);
    path.close();
    canvas.drawPath(path, paint);
  }

  @override
  bool shouldRepaint(CustomPainter oldDelegate) {
    return true;
  }
}

此代码给出以下结果：

Answer 2

您可以这样做

class LogoPainter extends CustomPainter {
  @override
  void paint(Canvas canvas, Size size) {
    Paint paint = Paint();
    paint.color = Colors.blue;
    Path path = new Path();
    path.lineTo(0, size.height - size.height / 5);
    //Use the method conicTo
    path.conicTo(size.width / 1.2, size.height, size.width,
        size.height - size.height / 5, 15);
    path.lineTo(size.width, 0);
    path.close();
    canvas.drawPath(path, paint);
  }

  @override
  bool shouldRepaint(covariant CustomPainter oldDelegate) {
    return true;
  }
}

result