Question

AERP|01,KSE;04,NCEL;05,GSE;|<END>

这是我的字符串现在我想将它分成两个数组，如

array1 = 01,04,05。 array2 = KSE，NCEL，GSE

并忽略"AERP|" & "|<END>".

注意：我在目标c。

工作

Answer 1

使用NSString componentsSeparatedByCharactersInSet

- (NSArray *)componentsSeparatedByCharactersInSet:(NSCharacterSet *)separator

构建您自己的NSCharacterSet使用NSMutableCharacterSet

NSMutableCharacterSet *_alnum = [NSMutableCharacterSet characterSetWithCharactersInString@"|"];

Answer 2

假设|，;，,是重要性递减的分隔符，我首先删除开头和结尾，然后分成数字/助记符对，然后分开对。它会是这样的：

NSString* input = @"AERP|01,KSE;04,NCEL;05,GSE;|<END>";
NSArray* splits = [input componentsSeparatedByString: @"|"];
// In real life, check that splits has three elements

NSString* body = [splits objectAtIndex: 1];
splits = [body componentsSeparatedByString: @";"];

NSMutableArray* numbers = [[NSMutableArray alloc] init];
NSMutableArray* mnemonics = [[NSMutableArray alloc] init];
for (NSString* item in splits)
{
    NSArray* parts = [item componentsSeparatedByString: @","];
    if ([parts count] == 2)
    {
        [numbers addObject: [parts objectAtIndex: 0]]; // Could convert the part to a number here 
                                                       // with NSDecimalNumber numberWithString: or alternative
        [mnemonics addObject: [parts objectAtIndex: 1]];
    }
}

Answer 3

NSString *stringToParse = [string substringWithRange:NSMakeRange(5, [string length] - 7)];
/* stringToParse = @"01,KSE;04,NCEL;05,GSE" */
NSArray *keyValuePairs = [stringToParse componentsSeparatedByString:@";"];
NSMutableArray *indices = [NSMutableArray array];
NSMutableArray *labels = [NSMutableArray array];
for (NSString *keyValueString in keyValuePairs) {
    NSArray *keyValuePairing = [keyValueString componentsSeparatedByString:@","]; 
    [indices addObject:[keyValuePairing objectAtIndex:0]];
    [labels addObject:[keyValuePairing objectAtIndex:1]];
}

Answer 4

NSString *astring=  @"AERP|01,KSE;04,NCEL;05,GSE;|<END>";
    NSArray *aq=[astring componentsSeparatedByString:@"|"];
    NSString *sw=[aq objectAtIndex:1];
    NSArray *aq2=[sw componentsSeparatedByString:@","];
    NSArray *aq3=[[aq2 objectAtIndex:1] componentsSeparatedByString:@";"];
    NSArray *aq4=[[aq2 objectAtIndex:2] componentsSeparatedByString:@";"];
    NSMutableArray *a1,*a2;
    a1=[NSMutableArray array];
    a2=[NSMutableArray array];
    [a1 addObject:[aq2 objectAtIndex:0]];
    [a1 addObject:[aq3 objectAtIndex:1]];
    [a1 addObject:[aq4 objectAtIndex:1]];
    [a2 addObject:[aq3 objectAtIndex:0]];
    [a2 addObject:[aq4 objectAtIndex:0]];
    [a2 addObject:[aq2 objectAtIndex:3]];

修改数组的名称，因为我已经快点完成了。

如何在iPhone中拆分字符串？

4 个答案: