我希望停止使用setTimeout运行的函数,并且不要在鼠标后面显示图像。我想用按钮点击这样做,怎么做? 我的代码:
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title></title>
<script type="text/javascript">
var trailimage = ["test.gif", 100, 99];
var offsetfrommouse = [-25, -25];
var displayduration = 0;
function truebody() {
return (!window.opera && document.compatMode && document.compatMode != "BackCompat") ? document.documentElement : document.body;
}
function hidetrail() {
var x = document.getElementById("trailimageid").style;
x.visibility = "hidden";
document.onmousemove = "";
}
function followmouse(e) {
var xcoord = offsetfrommouse[0];
var ycoord = offsetfrommouse[1];
if (typeof e != "undefined") {
xcoord += e.pageX;
ycoord += e.pageY;
}
else if (typeof window.event != "undefined") {
xcoord += truebody().scrollLeft + event.clientX;
ycoord += truebody().scrollTop + event.clientY;
}
var x = document.getElementById("trailimageid").style;
x.left = xcoord + "px";
x.top = ycoord + "px";
}
alert("obj_selected = true");
document.onmousemove = followmouse;
if (displayduration > 0)
setTimeout("hidetrail()", displayduration * 1000);
</script>
</head>
<body>
<form id="form1" runat="server">
<img alt="" id="trailimageid" src="Pictures/sides/sides-not-clicked.gif" border="0" style="position: absolute; visibility: visible; left: 0px;
top: 0px; width: 50px; height: 50px"/>
</form>
</body>
</html>
答案 0 :(得分:4)
var foobarTimeout = setTimeout(foobar, 1000);
...
clearTimeout(foobarTimeout);
请参阅:
https://developer.mozilla.org/en/DOM/window.setTimeout
https://developer.mozilla.org/en/DOM/window.clearTimeout
答案 1 :(得分:1)
保存setTimeout
的返回值,这是计时器的“句柄”,当您想取消它时,请使用该值调用clearTimeout
。
因此,在您的代码中,您需要在适当的位置声明timerHandle
变量,然后在此处设置:
if (displayduration > 0)
timerHandle = setTimeout("hidetrail()", displayduration * 1000);
...然后创建一个按钮click
处理程序:
function cancelTimeoutOnClick() {
if (timerHandle) {
clearTimeout(timerHandle);
timerHandle = 0;
}
}
偏离主题:将字符串传递给setTimeout
几乎绝不是最佳做法,这是隐式eval
。在您的情况下,只需传递函数引用:
if (displayduration > 0)
timerHandle = setTimeout(hidetrail, displayduration * 1000);
// ^--- Difference here (no quotes, no parentheses)
答案 2 :(得分:0)
你使用像&gt;
这样的超时var myTimeout = setTimeout(yourfunction);
然后你可以取消它&gt;
clearTimeout(myTimeout);