我在这里遇到了问题。请看我的代码。
use warnings;
use strict;
###ASK IMPUT FROM USER
print "Enter the Area: ";
my $area = <>;
print "Enter the Equipment: ";
my $equipment = <>;
print "Enter the Month: ";
my $month = <>;
print "Enter the Year: ";
my $year = <>;
###SUBROUTINE (FUNCTION) TO REMOVE THE WHITESPACE
sub rem_spaces {
my $t = shift || return(0); #Common practice: Use shift to take $t as a first parameter passed to the subroutine
$t =~ s/^\s+//; #remove leading spaces
$t =~ s/\s+$//; #remove trailing spaces
return $t;
}
####VARIABLE DECLARATION
my $REMOTE_HOST = "C:\\Users\\attmsbj1\\Desktop\\pic";
my $RESULT_FOLDER = "C:\\Users\\attmsbj1\\Desktop\\RESULT";
###CREATE FOLDER IF FOLDER DOES NOT EXIST.
if(-e $RESULT_FOLDER){
print "File exists.";
}
else {
mkdir ($RESULT_FOLDER);
}
###OPEN THE NEW FOLDER<br>
opendir (NewFolder, $RESULT_FOLDER) or die "Couldn't open the current directory: $!";
###OPEN PHOTOS FOLDER<br>
opendir (PicFolder, $REMOTE_HOST) or die "Couldn't open the current directory: $!";
@PicFolder =<PicFolder>;
###LOOP THROUGH ALL THE PICTURES IN THE FOLDER
foreach (@PicFolder)
{
if(###FULL STRING INPUT BY USER = PICFOLDER)
{
###MOVE OR COPY THE PICTURE TO THE NEW FOLDER
}
}
closedir PicFolder;
现在的问题是1)如何将用户输入的输入打印成1个字符串?
例如。面积:4;
设备:TQC
月:七月
年份:2011年
我想把它打印到4TQCJuly2011.jpg
我被困在循环中
感谢阅读和帮助。
其他细节 我的主要目标是创建一个perl脚本
我希望用户提供的输入格式为$ area $ equipment $ month $ year.jpg
它总是打印出来
4
TQC
JULY
2011
.JPG
而不是4TQCJULY2011.jpg(我想要这个结果)
答案 0 :(得分:0)
您可以在chomping
$area . $equipment . $month . $year
其他方法包括sprintf
$result = sprintf("%s%s%s%s", $area, $equipment, $month,$year);
有关详情
,请参阅perldoc -f sprintf
答案 1 :(得分:0)
我想我一定是在误解你的问题,但如果你想做的就是打印字符串$ area,$ equipment,$ month和$ year你为什么不用它?
print ($area.$equipment.$month.$year.".jpg");'?
答案 2 :(得分:0)
从vars中删除所有换行符
my $str = "$area$equipment$month$year.jpg";
$str =~ s/(\r|\n)//g; #you could potentially filter this more..
注意:我没有在Windows上执行perl所以这可能不是100%正确,linux我会使用mv
foreach my $cur (@PicFolder) {
if($str =~ /$cur/){
# I don't think this will work on windows.. `cp $PicFolder/$cur $NewFolder/$cur`;
#this might work..
rename ("$PicFolder/$cur, "$NewFolder/$cur" );
}
}
这应该可以帮助你开始..