E / AndroidRuntime:致命异常:主进程错误Android Studio

时间:2019-09-09 06:26:43

标签: android smsmanager

我编写了一个程序来发送短信,该短信在执行时会崩溃

public class MainActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    Button btnsend = (Button) findViewById(R.id.btnsend);
    final EditText edtnum = (EditText) findViewById(R.id.edtnum);
    final EditText edttext = (EditText) findViewById(R.id.edttext);



    btnsend.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) { 
            String phoneNo=edtnum.getText().toString();
            String message=edttext.getText().toString();
            SmsManager manager=SmsManager.getDefault();
            manager.sendTextMessage(phoneNo,null,message,null,null);

        }
    });

}

}

应用程序在按下按钮时崩溃并给出此错误

  

2019-09-09 10:30:33.384 2104-2104 / com.example.video60   E / AndroidRuntime:致命异常:main       流程:com.example.video60,PID:2104       java.lang.SecurityException:正在发送短信:uid 10086没有android.permission.SEND_SMS。           在android.os.Parcel.readException(Parcel.java:1942)           在android.os.Parcel.readException(Parcel.java:1888)           在com.android.internal.telephony.ISms $ Stub $ Proxy.sendTextForSubscriber(ISms.java:789)           在android.telephony.SmsManager.sendTextMessageInternal(SmsManager.java:329)           在android.telephony.SmsManager.sendTextMessage(SmsManager.java:312)           在com.example.video60.MainActivity $ 1.onClick(MainActivity.java:41)           在android.view.View.performClick(View.java:6256)           在android.view.View $ PerformClick.run(View.java:24697)           在android.os.Handler.handleCallback(Handler.java:789)           在android.os.Handler.dispatchMessage(Handler.java:98)           在android.os.Looper.loop(Looper.java:164)           在android.app.ActivityThread.main(ActivityThread.java:6541)           在java.lang.reflect.Method.invoke(本机方法)           在com.android.internal.os.Zygote $ MethodAndArgsCaller.run(Zygote.java:240)           在com.android.internal.os.ZygoteInit.main(ZygoteInit.java:767)

1 个答案:

答案 0 :(得分:1)

在您的android清单中,声明以下内容:

<uses-permission android:name="android.permission.SEND_SMS" />

因为您的异常告诉您:

  

发送SMS消息:uid 10086没有   android.permission.SEND_SMS。

您的应用无权发送短信

有关其他信息,请查看此:https://developer.android.com/guide/topics/permissions/overview

我的答案适用于api 22及以下版本,对于更高的权限,您必须请求权限,您可以在这里找到:https://developer.android.com/training/permissions/requesting

类似这样的东西:

if (ContextCompat.checkSelfPermission(thisActivity, Manifest.permission.SEND_SMS)
        != PackageManager.PERMISSION_GRANTED) {
    // Permission is not granted
}

// Here, thisActivity is the current activity
if (ContextCompat.checkSelfPermission(thisActivity,
        Manifest.permission.SEND_SMS)
        != PackageManager.PERMISSION_GRANTED) {

    // Permission is not granted
    // Should we show an explanation?
    if (ActivityCompat.shouldShowRequestPermissionRationale(thisActivity,
            Manifest.permission.SEND_SMS)) {
        // Show an explanation to the user *asynchronously* -- don't block
        // this thread waiting for the user's response! After the user
        // sees the explanation, try again to request the permission.
    } else {
        // No explanation needed; request the permission
        ActivityCompat.requestPermissions(thisActivity,
                new String[]{Manifest.permission.SEND_SMS},
                MY_PERMISSIONS_REQUEST_READ_CONTACTS);

        // MY_PERMISSIONS_REQUEST_READ_CONTACTS is an
        // app-defined int constant. The callback method gets the
        // result of the request.
    }
} else {
    // Permission has already been granted
}