actions.py

Question

我最近开始研究rasa。我的聊天机器人很简单。每当用户提出问题时，该漫游器就会从sqlite3数据库中过滤数据并返回结果。我添加了培训示例，为流程创建了故事，并编写了自定义操作以从数据库中过滤数据。对于自定义操作，我指定了一个端点并启动了操作服务器。到目前为止，这是我的代码

actions.py

from typing import Any, Text, Dict, List
from rasa_core_sdk import Action, Tracker
import sqlite3

class TestAction(Action):

    def name(self) -> Text:
        return "action_testAction"

    def run(self, dispatcher, tracker, domain):

        UserId = tracker.get_slot('UserID')
        query = 'SELECT User_name FROM sales WHERE UserID=?'

        conn = sqlite3.connect("test.db")
        cursor = conn.cursor()
        cursor.execute(query, (UserId,))
        name = cursor.fetchall()

        msg = 'Hello {}!'.format(name)
        dispatcher.utter_message(msg)

endpoints.yml

action_endpoint:
  url: "http://localhost:5055/"

为了运行端点，我在单独的终端窗口中运行了以下代码

python -m rasa_sdk --actions actions

但是当我基于此 link 使用rasa shell --endpoints endpoints.yml命令运行程序时，出现以下错误

rasa.core.processor  - Encountered an exception while running action 'action_testAction'. Bot will continue, but the actions events are lost. Please check the logs of your action server for more information.

这是我的动作端点服务器返回的内容

127.0.0.1 - - [2019-09-09 11:07:23] "POST / HTTP/1.1" 404 342 0.005443

我不确定我在做什么错。我检查了代码actions.py文件。我似乎没有在这里犯任何错误。

[编辑1]

我当时正在网上寻找并碰到了这个tutorial。

在本教程中，端点定义为

action_endpoint:   
    url: "http://localhost:5055/webhook"

现在我用我的代码尝试了相同的操作。当我使用更新的代码运行chatbot时，在action_server中出现以下异常

Exception: No registered Action found for name 'action_testAction'.

[编辑2]

在调试模式下运行动作服务器的结果

(base) SASHAANKs-MacBook-Pro:speechbot2 sashaanksekar$ rasa run actions -vv
2019-09-09 19:38:33 INFO     rasa_sdk.endpoint  - Starting action endpoint server...
2019-09-09 19:38:38 INFO     rasa_sdk.endpoint  - Action endpoint is up and running. on ('0.0.0.0', 5055)
2019-09-09 19:39:06 DEBUG    rasa_sdk.executor  - Received request to run 'action_testAction'
2019-09-09 19:39:06 ERROR    flask.app  - Exception on /webhook [POST]
Traceback (most recent call last):
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/flask/app.py", line 2292, in wsgi_app
    response = self.full_dispatch_request()
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/flask/app.py", line 1815, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/flask_cors/extension.py", line 161, in wrapped_function
    return cors_after_request(app.make_response(f(*args, **kwargs)))
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/flask/app.py", line 1718, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/flask/_compat.py", line 35, in reraise
    raise value
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/flask/app.py", line 1813, in full_dispatch_request
    rv = self.dispatch_request()
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/flask/app.py", line 1799, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/flask_cors/decorator.py", line 128, in wrapped_function
    resp = make_response(f(*args, **kwargs))
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/rasa_sdk/endpoint.py", line 59, in webhook
    response = executor.run(action_call)
  File "/Users/sashaanksekar/anaconda3/lib/python3.7/site-packages/rasa_sdk/executor.py", line 246, in run
    "No registered Action found for name '{}'.".format(action_name)
Exception: No registered Action found for name 'action_testAction'.

请帮助我

Answer 1

出现Exception: No registered Action found for name 'action_testAction'.错误的原因是由于运行动作服务器时遇到的第一个异常，即：

rasa.core.processor  - Encountered an exception while running action 'action_testAction'. Bot will continue, but the actions events are lost. Please check the logs of your action server for more information.

尝试使用debug mode之类的调试标志-vv在rasa run actions -vv中运行操作服务器，以查看代码中的问题所在。（问题可能是因为您可能尚未导入Action或sqlite3或其他任何东西。）

希望有帮助。

编辑：

确保action文件的名称匹配。

运行rasa run actions --actions action -vv，

(chatbot) PS C:\Users\user\Documents\Python\rasa-test> python -m rasa_sdk --actions action -vv
2019-09-09 21:02:56 INFO     rasa_sdk.endpoint  - Starting action endpoint server... 
2019-09-09 21:02:56 INFO     rasa_sdk.executor  - Registered function for 'action_testAction'.
2019-09-09 21:02:56 INFO     rasa_sdk.endpoint  - Action endpoint is up and running. on ('0.0.0.0', 5055)

action.py

import sqlite3

from rasa_sdk import Action

class TestAction(Action):

    def name(self):
        return "action_testAction"

    def run(self, dispatcher, tracker, domain):

        UserId = tracker.get_slot('UserID')
        query = 'SELECT User_name FROM sales WHERE UserID=?'

        conn = sqlite3.connect("test.db")
        cursor = conn.cursor()
        cursor.execute(query, (UserId,))
        name = cursor.fetchall()

        msg = 'Hello {}!'.format(name)
        dispatcher.utter_message(msg)

Answer 2

我遇到了这个错误，简单的解决方案是观察 actions.py 文件下面部分中的错误和代码。

class TestAction(Action):

    def name(self) -> Text:
        return "action_testAction"

类的名字是'TestAction'，'name'函数的返回值是'action_testAction'。所以错误是 - 您在域文件中使用的操作名称与此类中此“名称”方法返回的名称不匹配。在 NLU 训练数据和域文件中使用此“action_testAction”。

在rasa中运行自定义操作时遇到错误

actions.py

endpoints.yml

[编辑1]

[编辑2]

2 个答案: