我有两个桌子 1:-用户
id name
1 vivek
2 raj
3 mohan
4 gagan
5 priya
2:-购买
id typee user_id
1 class 1
2 class 1
3 course 1
4 class 2
5 test_series 3
6 test_series 2
我正在尝试运行
select p.id,(select count(purchasee.user_id) as tot
from purchasee
where purchasee.user_id=p.id
and typee='class'
or typee='course' ) as classcourse,(select count(purchasee.user_id) as tot
from purchasee
where purchasee.user_id=p.id
and typee='test_series') as test
from purchasee as p
GROUP by p.user_id
查询及其助我一臂之力
id Classcourse test
1 3 0
4 1 0
5 0 1
预期答案是
id Classcourse test
1 3 0
4 1 1
5 0 1
我要选择用户购买(班级或课程)或(test_series),如果是,则购买课程或课程,然后对其进行计数,或者如果用户购买test_series,然后计算行数
答案 0 :(得分:0)
尝试使用sql
SELECT p.id,
SUM( IF( typeee = 'class' || typeee = 'course', 1,0) ) as tot,
SUM( IF (typeee = 'test_series', 1,0) ) as classcourse
FROM purchasee as p
GROUP by p.user_id