我正在学习Java swing,这让我感到非常困惑。退出按钮不显示。但是,如果我将ID VALUE1 VALUE2 VALUE3
1 google [ab,c] Good
2 First [ab,c1] Good1
3 NaN [ab,c] Good
的代码部分移到按钮的两个部分之后,它将正确显示。那为什么呢?
textArea
答案 0 :(得分:2)
简单:添加JScrollPane之后,您忘记了重置c.gridheight = 1;
。如果不这样做,发送按钮将覆盖退出按钮。
private void launchFrame() {
panel = new JPanel(new GridBagLayout());
GridBagConstraints c = new GridBagConstraints();
c.fill = GridBagConstraints.HORIZONTAL; // ** This is also worthwhile **
textArea = new JTextArea(10, 50);
scrollPane = new JScrollPane(textArea);
c.gridx = 0;
c.gridy = 0;
c.gridheight = 3;
panel.add(scrollPane, c);
btnSend = new JButton("Send");
c.gridx = 1;
c.gridy = 0;
c.gridheight = 1; // ********* ADD THIS *********
c.anchor = GridBagConstraints.NORTH;
panel.add(btnSend, c);
btnQuit = new JButton("Quit");
c.gridx = 1;
c.gridy = 1;
c.anchor = GridBagConstraints.NORTH;
panel.add(btnQuit, c);
}